1 digit calculations just for orders of magnitude:
If we assume a doubling of CO2 is 4 W / m2 and the earth is 5 x 10^14 m2, a doubling of CO2 traps about 2 x 10^15 W.
If we assume 2 GtC / ppm, and think it takes say 300 ppm to double CO2, that is 600 GtC, 600 x 10^12 kgC = 6 * 10^14 GC, so each kgC in the atmosphere traps around 3 W.
Oil is about 4.5 x 10^7 J / kg. If we pretend oil is CH2, then we can assume that most of this mass is carbon, but a lot of the energy comes for the hydrogen. So by this reckoning it would take ( 4.5 x 10^7 J / kg ) / (3 W / kgC) = 1.5 * 10^7 s or less than half a year for the greenhouse gas to heat up as much as the thermal heating from the oil.
Of course, this CO2 is accumulating in the atmosphere.
If you think the airborne fraction on the margin, is around 0.5 over the first thousand years, giving you about the radiative heating each year equivalent to the chemical heating from burning. Then you get a few hundred thousand years with several fold less heating, with a cumulative radiative heating on the order of 100,000 times the direct chemical heating. (I am not going to quibble about small integer multipliers one way or the other.)
Of course, all of this heat will not go into melting ice.
(I think that 75 was the ratio of current atmospheric CO2 radiative forcing to direct heating from fossil fuel burning, but I would need to go back to check.)
___________________________________________________
Ken Caldeira
Carnegie Institution Dept of Global Ecology
260 Panama Street, Stanford, CA 94305 USA
kcal...@ciw.edu;
kcal...@stanford.edu
http://dge.stanford.edu/DGE/CIWDGE/labs/caldeiralab+1 650 704 7212; fax:
+1 650 462 5968