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Socratis
May 23, 2012, 5:55:23 AM5/23/12
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La formule ssuivante, pour trouvere le volume de
qualconque tronc de conus, en savant la valeur du conus
minime (dx^3)=o^3=4.71...cm^3.
Et, savant le numero de dx^3 relatif sur chaches seciones
du tronc de conus.
ex, dans l'interval, pour h, \ 7o a 9o \ on ha :
Sum,int.\ 7dy, 9dy \ = o*16dy = 75.39822..cm^3, (o^3).
o^3=(r^2*h*pi)/(3h^2)
o^3=((6o)^2*8o*pi)/(3*(8o)^2) = 4.71238898o^3
.
\/\/\/\/\/\/\/\/ 15o *o = 70.68583471 cm^3
\/\/\/\/\/\/\/ 13o *o = 61.26105674 cm^3
\/\/\/\/\/\/ 11o *o = 51.83627878 cm^3
\/\/\/\/\/ 9o *o = 42.41150082 cm^3
\/\/\/\/ 7o *o = 32.98672286 cm^3
\/\/\/ 5o *o = 23.56194490 cm^3
\/\/ 3o *o = 14.13716694 cm^3
\/ o *o = 4.712388980 cm^3
Socratis.
Socratis
May 23, 2012, 9:10:23 PM5/23/12
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"Socratis" <socr...@alice.it> ha scritto nel messaggio
--Errata corrige-
> La formule ssuivante, pour trouvere le volume de
> qualconque tronc de conus, en savant la valeur du conus
> minime (dx^3)=o^3=4.71...cm^3.
> Et, savant le numero de dx^3 relatif sur chaches sectione
> qualconque tronc de conus, en savant la valeur du conus
> minime (dx^3)=o^3=4.71...cm^3.
> du tronc de conus.
ex, dans l'interval, \ 4°, 5° \ on ha :
Sum,int.\ 7o^3 + 9o^3 \ = o^3 *16 = 75.39822..cm^3,
dh=dy=1cm.
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