auth.login function not working as expected

[Abraham Yusuf]

Hi all,
I'm trying to login a user using django's authentication backend with the following:
user=auth.authenticate(userid,pass)
if user:
if user.is_active:
auth.login(request,user)
I am getting TypeError login() takes exactly 1 argument (2 given). I've checked the docs and i can't find any problem there. Pls any help will be appreciated. Am using django 1.3.1, python 2.7 on ubuntu 11.04.

[Jhonny5]

Hi,

2011/12/18 Abraham Yusuf <bb...@yahoo.com>

Do you have maybe another function called login(one_argument).

Cheers,

J.

 

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[Jhonny5]

2011/12/18 Jhonny5 <jho...@gmail.com>

Hi,

2011/12/18 Abraham Yusuf <bb...@yahoo.com>

Hi all,
I'm trying to login a user using django's authentication backend with the following:
user=auth.authenticate(userid,pass)
if user:
  if user.is_active:
     auth.login(request,user)
I am getting TypeError login() takes exactly 1 argument (2 given). I've checked the docs and i can't find any problem there. Pls any help will be appreciated. Am using django 1.3.1, python 2.7 on ubuntu 11.04.

Do you have maybe another function called login(one_argument).

Just realize it's from auth object, but i had same problem with conflicts on that... check that way out maybe.

 

Cheers,

J.

 

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key: http://talueee.com/gpg/jhonny5.asc

Po fueno, po fale, po malegro.

[Abraham Yusuf]

Hi all,
I found a solution to the problem so i taught i'd let you know. It was really an oversight, my login view is like so:

@return_json
def login(request)

In the decorator i was ripping off the raw post data and passing it to the view as arguments while the view itself only takes the request arg. Sorry for posting it anyway.

[DrBloodmoney]

It sounds like you have solved your problem. In case you haven't, in
the auth.login() call above you have request <comma> user instead of
request <period> user. That would also give you the same error.