I'm working with Django's named URL patterns, and was wondering how to
fetch the name of the URL pattern that triggered the view. For
example, with the following urlpatterns

urlpatterns = patterns('',
    url(r'^archive/(\d{4})/$', archive, name="full-archive"),
    url(r'^archive-summary/(\d{4})/$', archive, {'summary': True},
"arch-summary"),
)

is there any way to fetch the name="full-archive" and
name="arch-summary" parameter from inside the view?

I found a thread that talks about this same issue
(http://stackoverflow.com/questions/1042211/get-name-for-matched-url-p...),
but the solution requires duplicating the URL pattern name in a
dictionary.

Thanks,