Display an URLField as a Link

[Tom]

My model :

url = models.URLField(max_length=500,blank=True,verify_exists=False)

and I want the column url display url as a link (<a href=""></a>)

Any ideas ?

Thanks for your help.

[Michael]

In general the models are for your database logic and display logic like this would be saved until your template. But since you insist, one easy way to accomplish this is by setting up a property on your model like so:

@property

def url_formatted(self):

     return '<a href="%s"></a>' % self.url

then you have a property on your model named url_formatted that will give you the output you desire.

I hope that helps,

Michael 

[Tom]

Thank you Michael,

Can you explain me the "Clean" way to do that ?

On May 8, 2:45 pm, Michael <newmani...@gmail.com> wrote:

[Michael]

On Mon, May 11, 2009 at 4:29 PM, Tom <thomas...@gmail.com> wrote:

Thank you Michael,

Can you explain me the "Clean" way to do that ?

Sure, you create a view (or use a generic view) that calls a template and has one of your models like so:

from django.shortcuts import render_to_response

from yourapp.models import YourModel

def yourview(request):

    m = YourModel.objects.order_by('?')[0]

    return render_to_response('yourtemplate.html', { 'object' : m})

and your template would then have a simple link like so

<a href="{{ object.url }}">{{ object.title }}</a>

Simple. I hope that helps,

Michael 

[Morgan]

In your template, you can use the "urlize" templatetag:

{{ mymodel.url|urlize }}

[Reiner]

Initially I thought you were talking about the admin, because of the
column url you mentioned. If that's the case, have a look at this part
of the documentation. You can define a property on your model, or if
you just want the admin to display it as a link, use a module-level
function or define it on your modeladmin. There are multiple ways of
accomplishing this.

http://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_display

[Tom]

Thanks for your help.

I used the http://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_display
method who work fine for me.

def url_as_link(self):
return '<a href="color: #%s;">%s</a>' % (self.url, self.url)
url_as_link.allow_tags = True

And call 'url_as_link' insted of 'url' in the ModelAdmin.

[pavan dhok]

its work for me.

# models.py #

class YourModel(models.Model):

        Website_list = models.URLField(max_length=5000)

        def url(self):
                return format_html("<a href='{url}' target='_blank'>{url}</a>", url=self.Website_list)

# admin.py #

list_display = ['url']