Get url parameters

[Hélio Miranda]

Hi

I need to get a parameter from the url and do not know how.

If my url looks like this: http://localhost:8080/test/view/20519364e38774a71190edb28c

I did like this:  url(r'^view/(?P<id>\w+)', 'rest.views.view'),

And everything ok.

Now I have a url like this: http://localhost:8080/test/view/<GridFSProxy: 20519364e38774a71190edb28c>

that the error looks like this: http://localhost:8080/test/view/%3CGridFSProxy:%20519364e38774a71190edb28c%3E

With a url so, how can I get only the number (20519364e38774a71190edb28c)?

Someone can help me?

[Sandro Dutra]

Your view is returning a GridFSProxy object, not a class/method
variable. You've to call a instance of your GridFSProxy, so you'll can
access the relative data.

2013/5/15 Hélio Miranda <heli...@gmail.com>:

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[Hélio Miranda]

So I mean the client side in my application I have to be able to access only the id, then just send the id and not <GridFSProxy: 519364e38774a71190edb28c>?

Could not sending as it is in django to extract just the number of the url?

[Sandro Dutra]

gfsp = GridFSProxy()
gfsp.variable

Where variable is the variable name that contains the data storing the
number you want yo retrieve. I think it can solve your problem.

2013/5/15 Hélio Miranda <heli...@gmail.com>:

[Hélio Miranda]

Hi

I need to get a parameter from the url which is the id and do not know how.

When my url is like this: http://localhost:8080/test/view/20519364e38774a71190edb28c

I do: url(r'^view/(?P<id>\w+)', 'rest.views.view'),

And everything ok.

Now I have a url like this: http://localhost:8080/test/view/<GridFSProxy:20519a3a6c8774a717dc59a84a>

that the error looks like this: http://localhost:8080/test/view/%3CGridFSProxy:%20519a3a6c8774a717dc59a84a%3E

With a url so, how can I get only the number (20519a3a6c8774a717dc59a84a)?

I'm trying this:

url(r'^view/.*Proxy:%(?P<id>\w+)%.*', 'rest.views.view'),

But it is giving, anyone know what I'm doing wrong?

Someone can help me?