> I'm working with Django's named URL patterns, and was wondering how to
> fetch the name of the URL pattern that triggered the view. For
> example, with the following urlpatterns

> urlpatterns = patterns('',
>     url(r'^archive/(\d{4})/$', archive, name="full-archive"),
>     url(r'^archive-summary/(\d{4})/$', archive, {'summary': True},
> "arch-summary"),
> )

> is there any way to fetch the name="full-archive" and
> name="arch-summary" parameter from inside the view?

> I found a thread that talks about this same issue
> (http://stackoverflow.com/questions/1042211/get-name-for-matched-url-p...),
> but the solution requires duplicating the URL pattern name in a
> dictionary.

> Thanks,

> Nick

> Hey everyone,

> I'm working with Django's named URL patterns, and was wondering how to
> fetch the name of the URL pattern that triggered the view. For
> example, with the following urlpatterns

> urlpatterns = patterns('',
>    url(r'^archive/(\d{4})/$', archive, name="full-archive"),
>    url(r'^archive-summary/(\d{4})/$', archive, {'summary': True},
> "arch-summary"),
> )

> is there any way to fetch the name="full-archive" and
> name="arch-summary" parameter from inside the view?

> I found a thread that talks about this same issue
> (http://stackoverflow.com/questions/1042211/get-name-for-matched-url-p...
> ),
> but the solution requires duplicating the URL pattern name in a
> dictionary.

> Thanks,

> Nick

> Hi,

> I came across a similar problem when trying to put together my app for
> handling menus (since I wanted to be able to specify menu items by url
> names).  Anyway the following was the method I finally came up with
> which seems to work just fine for me -
> http://code.google.com/p/greatlemers-django-tools/source/browse/trunk...

> Hope this helps.

> --
> G