I'm dabbling with generic views (thanks to wise advice from others on
this list), and I'm trying to convert one of my slightly more
complicated views to use a generic view. The vie itself is a simple
list, but my queryset is generated as follows:

Item.objects.filter(feed__feedtype__feedtype__iexact=re.sub('(s$|S$)',
'', feedtype)).order_by('-time')

What I'm trying to achieve here is not locking users into a certain
URL scheme - for the feedtype, I want uses to be able to specify
'/link', '/links', '/LINKS', and any combination thereof, hence the
regular expression which removes the trailing 's' from the request and
performs the case-insensitive query. This works fine when I use it in
a traditional view.

Now that I'm trying to use generic views (to avoid doing some ugly
pagination by hand), my urls.py line is as follows:

(r'^/?(?P<feedtype>\w+)/$',
'django.views.generic.list_detail.object_list', {'queryset':
Item.objects.filter(feed__feedtype__feedtype__iexact=re.sub('(s$|S$)',
'', feedtype)).order_by('-time'), 'paginate_by': 15, 'extra_context':
{'is_first_page': True}}),

However, the error which I get is as follows:

NameError at /photo/
name 'feedtype' is not defined
Request Method: GET
Request URL:    http://localhost:8000/photo/
Exception Type: NameError
Exception Value:        name 'feedtype' is not defined

I'm guessing that this is being caused by the regular expression
evaluation not seeing that 'feedtype' exists - is there a way to solve
this or will I have to use a standard view for this particular action?

--Jon

from django.views.generic.date_based import object_detail

@login_required
def limited_object_detail(*args, **kwargs):
    return object_detail(*args, **kwargs)

It might also help with the problem you are having.

Chris

On 8/15/06, Jon Atkinson <j...@jonatkinson.org> wrote:

If you do end up needing the RE, you could try using a custom manager
on your feeds model. Specifically, you could create a custom manager
method which filters based on the regular expression, then pass that
the captured feedtype from the URL.

See http://www.djangoproject.com/documentation/model_api/#managers for
details of custom managers and adding methods to them.

Michael

(r'^/?(?P<feedtype>\w+)/$',
'django.views.generic.list_detail.object_list', {'queryset':
Item.objects.filter(feed__feedtype__feedtype__iexact=feedtype).order_by('-t ime'),
'paginate_by': 15, 'extra_context': {'is_first_page': True}}),

And oddly enough I'm getting exactly the same error; is there another
problem with this statement which I'm not seeing? It seems there is a
problem with variable from the url expression being passed to the view
function - is this a common problem?

--Jon

On 8/15/06, Jon Atkinson <j...@jonatkinson.org> wrote:
[snip]

What's lacking in the generic object list is a "slugfield" similar to
what's found in generic object detail. If that existed, you'd be able
to do something like this:

(r'^/?(?P<filter>\w+)/$',
 'django.views.generic.list_detail.object_list',
 {'queryset': Item.objects.all().order_by('-time'),
 'filter_field':'feed__feedtype__feedtype__iexact',
 'paginate_by': 15 }),

Django would then substitute the captured "filter" variable into the
query-set like this:

Item.objects.all().order_by('-time').filter(
feed__feedtype__feedtype__iexact = captured_value )

I think it's worth raising a feature request in the Django Trac for
this functionality. I can imagine that this would be very useful to a
lot of people in the future.

Michael

It's the same thing as doing this in the Python interactive prompt:

    print a + 1

The variable "a" is not defined yet, so Python raises a NameError.

The problem in your case is that your view won't know the value of
feedtype until the URL is parsed. For that reason, you cannot put that
logic in the URLconf.

Adrian

--
Adrian Holovaty
holovaty.com | djangoproject.com

http://code.djangoproject.com/ticket/2544

--Jon

I've just read your reply _after_ I submitted the ticket - please do
close it if necessary.

Just out of interest, what do you think the most elegant way to solve
this problem would be? Is it to write my own view and deal with the
pagination myself?

Many thanks to all who replied to this thread.

--Jon