I m not familiar with django and I have found several problems trying
to sent a httpresponse with post parameters. I would like to return an
httpresponse (or httpredirect) to a new url with the request
parameters via post.

Could anybody help me?
Thank you in advance,
Miguel

I have defined a new view:

def prueba(request, seccion):
 if request.POST:
        new_data = request.POST.copy()

[get all the parameters]
[send a mail if correct]

        response = HttpResponse ("newUrl")
        #¿POST?
    return HttpResponseRedirect(response)

Hope it helps!

--
Antoni Aloy López
Blog: http://trespams.com
Site: http://apsl.net

The problem is that I need to redirect the request to an url and post to
this url the parameters I got from the initial request and display the post
url. Here is my views.py:

def prueba(request, seccion):

    if request.POST:
        new_data = request.POST.copy()

        Ds_Merchant_Titular = new_data['Ds_Merchant_Titular']
        Ds_Merchant_MerchantCode = new_data['Ds_Merchant_MerchantCode']
        Ds_Merchant_Amount = new_data['Ds_Merchant_Amount']
        Ds_Merchant_Currency = new_data['Ds_Merchant_Currency']
        Ds_Merchant_Order = new_data['Ds_Merchant_Order']

        correo_from = Ds_Merchant_Titular
        correo_asunto = "[contacto] " + Ds_Merchant_MerchantCode
        correo_to = []

       correo_to.append(MIEMAIL)
        correo_content = Ds_Merchant_Order

        sendMail(correo_to, correo_asunto, correo_content, True,
correo_from)
        params = urllib.urlencode({"Ds_Merchant_Titular":
Ds_Merchant_Titular, "Ds_Merchant_MerchantCode": Ds_Merchant_MerchantCode})
        #f= urllib2.urlopen("https://sis.sermepa.es/sis/realizarPago
",params)

   return f  -> it doesnt workd

   # return HttpResponseRedirect("https://sis.sermepa.es/sis/realizarPago",params)
--> it doesn't work

return HttpResponseRedirect("?".join(("
https://sis.sermepa.es/sis/realizarPago",params)))

but that won't force the client browser to use a POST when retrieving the
redirect location.  The redirect response contains a status code and
location, there is no field for the server to specify what method should be
used to access the specified location.  Standards actually specify that the
browser must use the same method as was used on the original request (which
seems to be what you want), but that is not, in fact, what most browsers
do.  See:

http://en.wikipedia.org/wiki/HTTP_302

Karen

thanks karen, that is what I meant.
So there is no way to return in my views.py an external web html with post
parameters ... it must be a way to do that, dont think so?

Karen, if I try your example
return HttpResponseRedirect("?".join(("
https://sis.sermepa.es/sis/realizarPago",params))), the web site is not
shown in the web browser I can see the url of my django place but not
https://sis.sermepa.es/sis/realizarPago.

Just check for httplib and httplib2.

http://code.activestate.com/recipes/146306/

or from Python documentation in http://docs.python.org/library/httplib.html

--
Antoni Aloy López
Blog: http://trespams.com
Site: http://apsl.net

well, I am not a python programmer and maybe I am doing silly things or this
is not as complex as I see but I not able to do what you mention above.
 I get the error,
'NoneType' object has no attribute 'read'

I have tried to follow http://code.activestate.com/recipes/146306/, with
only fields (the fields of my form) but I get stack here  return
h.file.read()  with the mentioned error.

I have also tried httplib.HTTPS but there is no way to get the results  I
wanted.
(i have also commeted  errcode, errmsg, header = ..., because i got some
errors)
here is my code:

    fields = [('Ds_Merchant_Titular', Ds_Merchant_Titular),( .........
]

    content_type, body = encode_multipart_formdata(fields)
    h = httplib.HTTPS("sis.sermepa.es",443)
    h.putrequest('POST', '/sis/realizarPago')
    h.putheader('content-type', content_type)
    h.putheader('content-length', str(len(body)))
    h.endheaders()
    h.send(body)
    #errcode, errmsg, headers = h.getreply()
    return h.file.read()

I have also tried with this code:

         ......
        data = urlencode(request.POST)
        resp, content = conn.request(u"
https://sis.sermepa.es/sis/realizarPago", 'POST', data)
        sys.stderr.write("\n\n\n\n mikimiki ----- " + content);
    return HttpResponse(content)

But here I get the URL of my django place in my browser instead of
https://sis.sermepa.es/sis/realizarPago. I mean, all the images and
resources are refered to relative paths and I not able to display the page.
For sure    return HttpResponse(content) is not the way as Antoni commented.

could anybody clarify me anything?

import httplib, urllib
params = urllib.urlencode({'this_is_the_login_form':1,'username':
'myuser', 'password': 'test'})
headers = {"Content-type": "application/x-www-form-urlencoded",
            "Accept": "text/plain"}
conn = httplib.HTTPConnection("myserver")
conn.request("POST", "/login/", params, headers)
response = conn.getresponse()
print response.status, response.reason

As I said, when hitting pages that do not require auth, I am
successful and get a 200 response code.  But when auth is needed, I
get 302 for the code and "found" for the status.

Any insights?

On Feb 17, 12:28 pm, Antoni Aloy <antoni.a...@gmail.com> wrote:

Not sure how this is related ot the original question in the thread,
though, which was about redirecting what the user's browser retrieves,
not retrieving web pages inside Python scripts.

Regards,
Malcolm

I write a experimental example to reach this requirement.  By AJAX
method, we can make a post type form after server answer.

my example is below here:

http://hoamon.blogspot.com/2009/03/return-httpresponseredirect-by-pos...