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VP8 partition question
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Subject: Re: VP8 partition question
From: Mamadou <boss...@yahoo.fr>
To: discuss-webrtc <discuss-webrtc@googlegroups.com>
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You're not looking at the right place. For RTP packetization:
http://tools.ietf.org/html/draft-ietf-payload-vp8-03
The right field is 'PartID' which takes 4bits. For more information:
'4.2. VP8 Payload Descriptor'
For example:
- Packetization:
http://code.google.com/p/doubango/source/browse/branches/2.0/doubango/tinyD=
AV/src/codecs/vpx/tdav_codec_vp8.c#636
- Depacketization:
http://code.google.com/p/doubango/source/browse/branches/2.0/doubango/tinyD=
AV/src/codecs/vpx/tdav_codec_vp8.c#345
On Aug 3, 4:17=A0pm, chrisgNH <cgo...@iocom.com> wrote:
> RFC 6386 Talks about multiple data partitions, and states in part: "A
> two-bit L(2) is used to indicate the number of
> =A0 =A0coefficient data partitions within a compressed frame. =A0The two =
bits
> =A0 =A0are defined in the following table..."
>
> My question is: Where are these two bits located in the data stream? =A0W=
ill
> these 2 bits always be there - or only when there are more than the two
> default partitions? =A0I have VP8 encoding working, and I'm currently
> implementing RTP packetization. =A0I've looked at the ietf draft for VP8
> packetization as well. =A0While this does mention multiple data partition=
s,
> and that they will be contiguous in the bitstream, I'm unclear as to how =
to
> determine if there are more than 2 partitions.
>
> Any help would be appreciated.
> Thanks.