Re: [cython-users] Cannot convert Python object to 'Handle *'

[Robert Bradshaw]

On Mon, Nov 5, 2012 at 10:07 PM, RC <rav...@gmail.com> wrote:
> I am trying to wrap a cpp lib into cython. Here are some details:
>
> Handle.h:
>
> class Handle {
> public:
> // accessors
> // mutators
> };
>
> class Store {
> public:
> Handle* lookup(char* handleName);
> int update(Handle*);
> };
>
> handle.pyx:
>
> cdef extern from "Handle.h" namespace "xxx":
> cdef cppclass Handle:
> ....
>
> cdef extern from "Handle.h" namespace "xxx":
> cdef cppclass Store:
> Handle* lookup(char*)
> int update(Handle*)
>
> cdef class PyHandle:
>
> cdef class PyStore:
> cdef Store* store
> def __cinit__(self):
> store = ....
> def lookup(self, name):
> handle = self.store.lookup(name)
> pHandle = PyHandle()
> pHandle.handle = handle
> return pHandle
> def update(self, h):
> self.store.update(h.handle)
>
> the last statement is giving me an error saying "Cannot convert Python
> object to 'Handle *'". I know i am missing something simple. How do i pass
> the handle* that is embedded in the python object to the call?

On the vary last line, all it knows is that h is a Python object. You
probably meant to say

def update(self, PyHandle h):
self.store.update(h.handle)

- Robert