};

};

On Mon, Nov 5, 2012 at 10:07 PM, RC <ravi...@gmail.com> wrote:
> I am trying to wrap a cpp lib into cython. Here are some details:

> Handle.h:

> class Handle {
>     public:
>        // accessors
>        // mutators
> };

> class Store {
>      public:
>          Handle* lookup(char* handleName);
>          int update(Handle*);
> };

> handle.pyx:

> cdef extern from "Handle.h" namespace "xxx":
>     cdef cppclass Handle:
>             ....

> cdef extern from "Handle.h" namespace "xxx":
>    cdef cppclass Store:
>           Handle* lookup(char*)
>           int update(Handle*)

> cdef class PyHandle:

> cdef class PyStore:
>     cdef Store* store
>     def __cinit__(self):
>         store = ....
>     def lookup(self, name):
>          handle = self.store.lookup(name)
>          pHandle = PyHandle()
>          pHandle.handle = handle
>          return pHandle
>     def update(self, h):
>         self.store.update(h.handle)

> the last statement is giving me an error saying "Cannot convert Python
> object to 'Handle *'". I know i am missing something simple. How do i pass
> the handle* that is embedded in the python object to the call?

On Monday, November 5, 2012 11:45:47 PM UTC-8, Robert Bradshaw wrote:

> On Mon, Nov 5, 2012 at 10:07 PM, RC <rav...@gmail.com <javascript:>>
> wrote:
> > I am trying to wrap a cpp lib into cython. Here are some details:

> > Handle.h:

> > class Handle {
> >     public:
> >        // accessors
> >        // mutators
> > };

> > class Store {
> >      public:
> >          Handle* lookup(char* handleName);
> >          int update(Handle*);
> > };

> > handle.pyx:

> > cdef extern from "Handle.h" namespace "xxx":
> >     cdef cppclass Handle:
> >             ....

> > cdef extern from "Handle.h" namespace "xxx":
> >    cdef cppclass Store:
> >           Handle* lookup(char*)
> >           int update(Handle*)

> > cdef class PyHandle:

> > cdef class PyStore:
> >     cdef Store* store
> >     def __cinit__(self):
> >         store = ....
> >     def lookup(self, name):
> >          handle = self.store.lookup(name)
> >          pHandle = PyHandle()
> >          pHandle.handle = handle
> >          return pHandle
> >     def update(self, h):
> >         self.store.update(h.handle)

> > the last statement is giving me an error saying "Cannot convert Python
> > object to 'Handle *'". I know i am missing something simple. How do i
> pass
> > the handle* that is embedded in the python object to the call?

> On the vary last line, all it knows is that h is a Python object. You
> probably meant to say

>     def update(self, PyHandle h):
>         self.store.update(h.handle)

> - Robert