[[ b == [A-B] ]]; echo $? # returns 0 in bash. why?

[Name withheld by request]

pls explain:

$ [[ b == [A-B] ]]; echo $?
0
$ [[ b == [B] ]]; echo $?
1
$ [[ b == [b] ]]; echo $?
0
$ echo $BASH_VERSION
4.1.10(4)-release

--
thanks

[Christian Barthel]

If you want to compare a string:

STRING1 = STRING2
the strings are equal

If you want to compare a number:

INTEGER1 -eq INTEGER2
INTEGER1 is equal to INTEGER2

See also:
man test
>
> --
> thanks

[Janis Papanagnou]

You are answering to a very old posting, and apparently haven't read
the replies given at that time; you completely missed the OP's point.

Janis

BTW, man test may be misleading if using the [[...]] shell built-in.

>>
>> --
>> thanks

[Kenny McCormack]

In article <jglshl$2c3$1...@news.m-online.net>,
Janis Papanagnou <janis_pa...@hotmail.com> wrote:
...

>You are answering to a very old posting, and apparently haven't read
>the replies given at that time; you completely missed the OP's point.

Yes, but completely missing OPs' point(s) is the whole point of Usenet.

--
"We should always be disposed to believe that which appears to us to be
white is really black, if the hierarchy of the church so decides."

- Saint Ignatius Loyola (1491-1556) Founder of the Jesuit Order -

[Eric_DL]

Name withheld by request <anon...@nyx3.nyx.net> wrote:

Hi,

It may be because of your curent locale setting (command line is "locale").
If your locale sort alphanumeric characters this way : a,A,b,B,c,C,...
then b is actually in the interval [A-B].
Check section "Pattern Matching" in :
http://www.linuxcommand.org/man_pages/bash1.html to see the influence of
the LC_COLLATE shell variable.

Cheers
Eric


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