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Newsgroups: comp.unix.programmer
Subject: Re: parsing a bibtex file
Date: Sun, 23 Sep 2012 23:50:30 +0100
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Ben,=20
Thanks for your reply.
I am trying to learn parsing (and may be scrapping some time later),
which means, I should not use ready-to-use solution(its self assigned
work, please don't assume I am asking you to solve my homework).
As in the first post in this thread, I stated that, I need to store
value of each author token.
So, if in my bibtex file has entries like:
@article{mrx05,=20
Author =3D "Mr. X",=20
Title =3D {Something Great},=20
Publisher =3D "nob" # "ody"},=20
Year =3D 2005,=20
}=20
@article{mra12,=20
Author =3D "Mr. A and Mr. B",=20
Title =3D {Something Equally Great},=20
Publisher =3D "nob" # "ody"},=20
Year =3D 2012,=20
}=20

I would like to have
array_author[0]=3D"Mr. X"
array_author[1]=3D"Mr. A and Mr. B"

array_year[0]=3D2005
array_year[1]=3D2012

and so on.
For completeness, I am pasting the flex code that I have managed(copy
from the first post). It parses everything correctly, but I don't know
how to store the results in array. Please help.

$ cat pbib.l=20
%{
#include <stdio.h>
#include <stdlib.h>
%}

%{
char yylval;
int YEAR;
%}
%x author
%x title
%x pub
%x year
%%
@[a-zA-Z][a-zA-Z0-9]*   { printf("%s",yytext);}
[Aa]uthor=3D                 {BEGIN(author);}
<author>\"[a-zA-Z\/.]+\"  { printf("%s",yytext);
                           BEGIN(INITIAL);}
[Yy]ear=3D                   {BEGIN(year);}
<year>\"[0-9]+\"        {printf("%s",yytext);
                        BEGIN(INITIAL);}
[Tt]itle=3D                 {BEGIN(title);}
<title>\"[a-zA-Z\/.]+\"  { printf("%s",yytext);
                           BEGIN(INITIAL);}
[Pp]ublisher=3D                 {BEGIN(pub);}
<pub>\"[a-zA-Z\/.]+\"  { printf("%s",yytext);
                           BEGIN(INITIAL);}
[a-zA-Z0-9\/.-]+=3D        printf("ENTRY TYPE ");
\"                      printf("QUOTE ");
\{                      printf(" ");
\}                      printf(" ");
;                       printf("SEMICOLON ");
\n                      printf("\n");
[\,\n\}][\,\}]          printf("\nNEWENTRY");
%%