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Jerry
Nov 15, 2012, 3:35:15 PM11/15/12
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Hello,
A=rand (201,7152);
"A" is a matrix and I would like to reshape "A" to "B"
B=reshape (A,59898,24);
"B" is not going to be what I expected since it is getting mixed up. For example
C=A(:,1:24);
D=B(1:201,:);
isequal(C, D)
ans =
0
How can I reshape "A" to get "C" equal with "D".
Thanks,
Jerry
A=rand (201,7152);
"A" is a matrix and I would like to reshape "A" to "B"
B=reshape (A,59898,24);
"B" is not going to be what I expected since it is getting mixed up. For example
C=A(:,1:24);
D=B(1:201,:);
isequal(C, D)
ans =
0
How can I reshape "A" to get "C" equal with "D".
Thanks,
Jerry
Roger Stafford
Nov 15, 2012, 7:43:15 PM11/15/12
to
"Jerry " <jerry...@gmail.com> wrote in message <k83jm3$4o1$1...@newscl01ah.mathworks.com>...
- - - - - - - - -
To get the kind of rearrangement you have in mind takes more than a simple 'reshape'. One has to do a little permuting first. Do this:
r = 298; % The number of your blocks
[p,t] = size(A); % p = 201, t = 7152
q = t/r; % t must be divisible by r, q = 24
s = 0:p*q*r-1;
B = reshape(A(1+s+p*((q-1)*floor(s/p)-(q*r-1)*floor(s/(p*r)))),p*r,q);
Roger Stafford
To get the kind of rearrangement you have in mind takes more than a simple 'reshape'. One has to do a little permuting first. Do this:
r = 298; % The number of your blocks
[p,t] = size(A); % p = 201, t = 7152
q = t/r; % t must be divisible by r, q = 24
s = 0:p*q*r-1;
B = reshape(A(1+s+p*((q-1)*floor(s/p)-(q*r-1)*floor(s/(p*r)))),p*r,q);
Roger Stafford
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