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Jerry  
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 More options Nov 15 2012, 3:35 pm
Newsgroups: comp.soft-sys.matlab
From: "Jerry " <jerrych...@gmail.com>
Date: Thu, 15 Nov 2012 20:35:15 +0000 (UTC)
Local: Thurs, Nov 15 2012 3:35 pm
Subject: Reshape
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Hello,

A=rand (201,7152);

"A" is a matrix and I would like to reshape "A" to "B"

B=reshape (A,59898,24);

"B" is not going to be what I expected since it is getting mixed up. For example

C=A(:,1:24);
D=B(1:201,:);

isequal(C, D)

ans =

     0
How can I reshape "A" to get "C" equal with "D".

Thanks,
Jerry


 
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Roger Stafford  
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 More options Nov 15 2012, 7:43 pm
Newsgroups: comp.soft-sys.matlab
From: "Roger Stafford" <ellieandrogerxy...@mindspring.com.invalid>
Date: Fri, 16 Nov 2012 00:43:15 +0000 (UTC)
Local: Thurs, Nov 15 2012 7:43 pm
Subject: Reshape
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- - - - - - - - -
  To get the kind of rearrangement you have in mind takes more than a simple 'reshape'.  One has to do a little permuting first.  Do this:

 r = 298; % The number of your blocks
 [p,t] = size(A); % p = 201, t = 7152
 q = t/r; % t must be divisible by r, q = 24
 s = 0:p*q*r-1;
 B = reshape(A(1+s+p*((q-1)*floor(s/p)-(q*r-1)*floor(s/(p*r)))),p*r,q);

Roger Stafford


 
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