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Alaska
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Kevin J. McCann
May 1, 2012, 5:24:54 AM5/1/12
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Apparently Alaska is part of the World, but not of USA or NorthAmerica!!
Try:
Graphics@CountryData["USA", "Polygon"]
Graphics@CountryData["NorthAmerica", "Polygon"]
Graphics@CountryData["World", "Polygon"]
I know that Wolfram has defined the Pound to be a mass rather than a
force, but to miss Alaska ...
Cheers,
Kevin
Try:
Graphics@CountryData["USA", "Polygon"]
Graphics@CountryData["NorthAmerica", "Polygon"]
Graphics@CountryData["World", "Polygon"]
I know that Wolfram has defined the Pound to be a mass rather than a
force, but to miss Alaska ...
Cheers,
Kevin
David Reiss
May 1, 2012, 2:59:54 PM5/1/12
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It is a reported bug... and I have been nudging them for a long time
to fix this.
István Zachar
May 1, 2012, 2:57:51 PM5/1/12
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Dear Kevin,
You might find this Mathematica.SE answer useful which I recieved for one of my similar questions: http://mathematica.stackexchange.com/a/3648/89
In a nutshell: "Polygon" only gives the main boundaries of a country, an as such, "Polygon" is not the direct simplification of "FullPolygon", as it omits certain parts. Use "FullPolygon" for all boundaries (though be prepared that it takes more time as it uses much more polygon points).
Istvan
You might find this Mathematica.SE answer useful which I recieved for one of my similar questions: http://mathematica.stackexchange.com/a/3648/89
In a nutshell: "Polygon" only gives the main boundaries of a country, an as such, "Polygon" is not the direct simplification of "FullPolygon", as it omits certain parts. Use "FullPolygon" for all boundaries (though be prepared that it takes more time as it uses much more polygon points).
Istvan
István Zachar
May 1, 2012, 7:59:47 PM5/1/12
to
Dear Kevin,
You might find this Mathematica.SE answer useful which I recieved for one of my similar questions: http://mathematica.stackexchange.com/a/3648/89
In a nutshell: "Polygon" only gives the main boundaries of a country, an as such, "Polygon" is not the direct simplification of "FullPolygon", as it omits certain parts. Use "FullPolygon" for all boundaries (though be prepared that it takes more time as it uses much more polygon points).
Istvan
On Tuesday, May 1, 2012 10:24:54 AM UTC+1, Kevin J. McCann wrote:
You might find this Mathematica.SE answer useful which I recieved for one of my similar questions: http://mathematica.stackexchange.com/a/3648/89
In a nutshell: "Polygon" only gives the main boundaries of a country, an as such, "Polygon" is not the direct simplification of "FullPolygon", as it omits certain parts. Use "FullPolygon" for all boundaries (though be prepared that it takes more time as it uses much more polygon points).
Istvan
On Tuesday, May 1, 2012 10:24:54 AM UTC+1, Kevin J. McCann wrote:
Kevin J. McCann
May 3, 2012, 4:39:05 AM5/3/12
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Thanks David,
I am surprised that it hasn't been fixed, especially since Wolfram is
touting all this sort of data base stuff. Not much documentation on it
either.
Kevin
I am surprised that it hasn't been fixed, especially since Wolfram is
touting all this sort of data base stuff. Not much documentation on it
either.
Kevin
Kevin J. McCann
May 3, 2012, 4:38:34 AM5/3/12
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Thanks Istvan,
It works. It is interesting that "Polygon","FullPolygon", and
"SchematicPolygon" return results that differ so much.
Kevin
It works. It is interesting that "Polygon","FullPolygon", and
"SchematicPolygon" return results that differ so much.
Kevin
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