1)NDSolve::dvlen: The function x[t] does not have the same number of arguments as independent variables (3). >>
2)ReplaceAll::reps: {NDSolve[{x[t]/3+(x^\[Prime]\[Prime])[t]==0,x[0]==5,(x^\[Prime])[0]==0},x,{ t,0,250},MaxSteps\[RightArrow]50000,WorkingPrecision\[RightArrow]25]} is neither a list of replacement rules nor a valid dispatch table, and so cannot be used for replacing. >>
3)ParametricPlot::pllim: Range specification PlotRange\[RightArrow]All is not of the form {x, xmin, xmax}. >>
When I copied and pasted your input I had the same error. However,
after I manually re-entered the line defining solution all worked
well. You must have some invisible character in your input.
Bob Hanlon
On Tue, May 15, 2012 at 4:54 AM, Rahul Chakraborty
==5,(x^\[Prime])[0]==0},x,{t,0,250},MaxSteps\[RightArrow]50000,Work=
ingPrecision\[RightArrow]25]} is neither a list of replacement rules nor a =
valid dispatch table, and so cannot be used for replacing. >>
> 3)ParametricPlot::pllim: Range specification PlotRange\[RightArrow]All is=
replace in your expression \[RightArrow] by \[Rule] (delete the arrows and retype them properly).
If you look on the documentation for \[RightArrow]
you will find that it has no built-in meaning and that it can be entered
as [ESC]_->[ESC], where _ stands for an extra space, while \[Rule] is
entered as [ESC]->[ESC] only.
In the email text it is easy to see the difference between \[RightArrow] and \[Rule], to
see the difference in your notebook just press Shift+Ctrl+E inside the cell or use
Hold[expr]//FullForm to see the unevaluated fullform of the expression.
Best,
Christoph
Addendum: another issue is, that the error messages of the present example are not really
related to the problem, does anyone know why?
> 1)NDSolve::dvlen: The function x[t] does not have the same number of arguments as independent variables (3).>>
> 2)ReplaceAll::reps: {NDSolve[{x[t]/3+(x^\[Prime]\[Prime])[t]==0,x[0]==5,(x^\[Prime])[0]==0},x,{ t,0,250},MaxSteps\[RightArrow]50000,WorkingPrecision\[RightArrow]25]} is neither a list of replacement rules nor a valid dispatch table, and so cannot be used for replacing.>>
> 3)ParametricPlot::pllim: Range specification PlotRange\[RightArrow]All is not of the form {x, xmin, xmax}.>>
The main difference in the function Flatten that I apply to the solution. I t removes the extra parentheses. The latter have prevented you from getting solution.