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int(exp(x^n),x) and Ei

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Thomas D. Dean

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Jan 13, 2012, 4:13:35 PM1/13/12
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Wolfram gives the result of

integrate(exp(x^n),x) as

integrate(exp(x^n),x) = -x*Ei[(n-1)/n](-x^n)/n

http://integrals.wolfram.com/index.jsp?expr=exp(x^n)&random=false

Maple just returns the original expression.

How do I get the Ei form?

Tom Dean

Axel Vogt

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Jan 14, 2012, 3:17:41 AM1/14/12
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There should be no integration variable in the result.

G. A. Edgar

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Jan 14, 2012, 8:59:24 AM1/14/12
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In article <0q6dnULAAoXiA43S...@megapath.net>, Thomas D.
I think you cannot do that in Maple. That E with subscript is just a
re-writing of the original integral anyway... and Maple does not
include that variant. Using an actual value for n, Maple can produce
the incomplete Gamma versions...

integrate(exp(x^7),x)
after simplifying gets me to
(1/7)*exp(-((1/7)*I)*Pi)*(GAMMA(1/7)-GAMMA(1/7, -x^7))
and you can of course adjust the constant of integration.
So, interestingly, both Maple and Alpha use complex numbers to
represent this real integral.

--
G. A. Edgar http://www.math.ohio-state.edu/~edgar/

Peter Pein

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Jan 14, 2012, 2:40:36 PM1/14/12
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convert("-x*Ei[(n-1)/n](-x^n)/n", FromMma);

G. A. Edgar

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Jan 15, 2012, 8:45:39 AM1/15/12
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In article <jeslnl$8f4$1...@online.de>, Peter Pein <pet...@dordos.net>
wrote:
maybe...

convert("-x*Ei[(n-1)/n,-x^n]/n", FromMma);

But even if Maple returns something, it doesn't know what it is.
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