As you could see, there is a g^(2/3) which is a common factor...
If provided in machine-readable form, we could try it out and see if we
could do it.
It seems that you could define g'=g^(1/3) and almost have a polynomial.
Okay, here is an example:
-(1/12)*(-g*vb-g+z*g-g^(2/3)*z+g^(2/3)*vb)*(g^(1/3)+1)^5/g^(2/3)
Just wanted to get rid of the denominator...
OKay, suppose I have a very complicated expression involving g^(1/3)
and g^(2/3), how do I replace all those factors using g' in Maple?
Thanks
A := -(1/12)*(-g*vb-g+z*g-g^(2/3)*z+g^(2/3)*vb)*(g^(1/3)+1)^5/g^(2/3);
expand(A);
no denominator
Thanks. I am thinking that the best way to go is to define g1=g^(1/3),
g2=g^(2/3) and then replace all those items...
how to do that in Maple?
Thanks!
Do it in the standard way: subs({g^(1/3) = g1, g^(2/3) = g2},expr);
However, if you had an expression containing, say g^(4/3) as well,
Maple would just leave it, rather than writing g1^4 or g2^2.
Judging from the questions you have been posting here, it seems that
you would benefit greatly form a BOOK on Maple usage.
R.G. Vickson
>
> Thanks!