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barcaroller  
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 More options May 15 2007, 6:31 pm
Newsgroups: comp.protocols.tcp-ip
From: "barcaroller" <barcarol...@music.net>
Date: Tue, 15 May 2007 18:31:44 -0400
Local: Tues, May 15 2007 6:31 pm
Subject: TCP handshake question...
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Client                          Server
       -------- SYN J -------->
       <--- SYN K, ACK J+1 ----
       ------- ACK K+1 ------->

During TCP connection establishment (above), the third segment is an ACK
from the client to the server.  What is the sequence number in that segment?
Is it J or J+1 or 0 or some other value?


 
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Jim Logajan  
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 More options May 15 2007, 7:41 pm
Newsgroups: comp.protocols.tcp-ip
From: Jim Logajan <Jam...@Lugoj.com>
Date: Tue, 15 May 2007 23:41:32 -0000
Local: Tues, May 15 2007 7:41 pm
Subject: Re: TCP handshake question...
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"barcaroller" <barcarol...@music.net> wrote:
> Client                          Server
>        -------- SYN J -------->
>        <--- SYN K, ACK J+1 ----
>        ------- ACK K+1 ------->

> During TCP connection establishment (above), the third segment is an
> ACK from the client to the server.  What is the sequence number in
> that segment? Is it J or J+1 or 0 or some other value?

Figure 7 in RFC0793 shows the same handshake, but with the additional
detail needed to answer your question. The sequence number in the third
segment is shown as J+1.

In general, any TCP segment containing a set FIN flag, a set SYN flag,
and/or data must advance the sequence number. Any segment void of all three
of those sequence-number-consuming aspects should contain the current
sequence number.


 
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Justa Lurker  
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 More options May 15 2007, 8:56 pm
Newsgroups: comp.protocols.tcp-ip
From: Justa Lurker <JustaLur...@att.net>
Date: Wed, 16 May 2007 00:56:25 GMT
Local: Tues, May 15 2007 8:56 pm
Subject: Re: TCP handshake question...
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barcaroller wrote:
> Client                          Server
>        -------- SYN J -------->
>        <--- SYN K, ACK J+1 ----
>        ------- ACK K+1 ------->

> During TCP connection establishment (above), the third segment is an ACK
> from the client to the server.  What is the sequence number in that segment?
> Is it J or J+1 or 0 or some other value?

Here is a question for you ...... when is the homework or takehome exam
due ?

 
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chunhui  
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 More options May 16 2007, 5:59 am
Newsgroups: comp.protocols.tcp-ip
From: chunhui <chunhui_t...@163.com>
Date: Wed, 16 May 2007 09:59:40 +0000
Local: Wed, May 16 2007 5:59 am
Subject: Re: TCP handshake question...
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barcaroller 写道:
> Client                          Server
>        -------- SYN J -------->
>        <--- SYN K, ACK J+1 ----
>        ------- ACK K+1 ------->

> During TCP connection establishment (above), the third segment is an ACK
> from the client to the server.  What is the sequence number in that segment?
> Is it J or J+1 or 0 or some other value?

 I use tcpdump to capture a FTP link.and the result is J + 1.

--

                              chunhui_t...@163.com


 
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