How to make a cycling counter from commandline?
dare...@gmail.com
-------------------------------------
count=1
total=15
until count>total
print "Record #{count} of #{total} processed."
count+=1
end
-------------------------------------
I want this to print out in a Linux shell. However, I'd prefer it if
there was a way to have this counter increment without printing a new
line. As in, from the user's perspective the 'count' would just
increment until it matched the total... all taking place on the same
line.
I know I've seen this done, but can Ruby do this?
Jan Svitok
Search the archives for count or counter. It was discussed last week or so.
Tim Pease
>
>
> -------------------------------------
> count=1
> total=15
>
> until count>total
> print "Record #{count} of #{total} processed."
> count+=1
> end
> -------------------------------------
>
>
$ cat tmp.rb
STDOUT.sync = true
total = ARGV[0] || 15
count = 1
until count>total
print "\rRecord #{count} of #{total} processed"
count += 1
sleep 0.25
end
print "\n"
That should do you what you want. The secret is the carriage return
"\r" at the beginning of the print string. That will bring the cursor
back to the beginning of the line and then overwrite anything
currently on that line.
Blessings,
TwP
Tim Pease
> On 11/7/06, dare...@gmail.com <dare...@gmail.com> wrote:
> > Hi, I'm looking for a way to implement this idea:
> >
> >
> > -------------------------------------
> > count=1
> > total=15
> >
> > until count>total
> > print "Record #{count} of #{total} processed."
> > count+=1
> > end
> > -------------------------------------
> >
> >
>
> $ cat tmp.rb
>
> STDOUT.sync = true
>
> total = ARGV[0] || 15
total = ARGV[0] || 15
total = Integer(total) # need to turn any passed in arguments into an integer
ara.t....@noaa.gov
> $ cat tmp.rb
>
> STDOUT.sync = true
>
> total = ARGV[0] || 15
> count = 1
>
> until count>total
> print "\rRecord #{count} of #{total} processed"
> count += 1
> sleep 0.25
> end
>
> print "\n"
>
>
> That should do you what you want. The secret is the carriage return
> "\r" at the beginning of the print string. That will bring the cursor
> back to the beginning of the line and then overwrite anything
> currently on that line.
>
> Blessings,
> TwP
man, you learn something every day! that's pretty sweet.
-a
--
my religion is very simple. my religion is kindness. -- the dalai lama
Carlos
From my BBS years I remember adding... mmm... ¿"\033[K"? at the end of
the string when I did this kind of overwriting. That ANSI code (if I
remembered it correctly) clears everything until the end of line
--useful in case the new string is shorter than the overwritten one.
(This doesn't happen in this case, but maybe the OP wants to print
"#{total} record processed" afterwards.)
Greetings.
--
Tim Pease
>
> From my BBS years I remember adding... mmm... ¿"\033[K"? at the end of
> the string when I did this kind of overwriting. That ANSI code (if I
> remembered it correctly) clears everything until the end of line
> --useful in case the new string is shorter than the overwritten one.
> (This doesn't happen in this case, but maybe the OP wants to print
> "#{total} record processed" afterwards.)
>
Yeah, that was the fatal flaw in my little post there. That is one
very cool ANSI code though. I've used the color codes, but did not
know about that one :)
I just tried it out, and that is the correct code :)
clear = "\e[K"
print "a very long line of text that is longer than the next line"
sleep 1
print "\rshort line of text#{clear}"
sleep 1
print "\n"
By the way "\e" == "\033"
Blessings,
TwP
David Vallner
> That should do you what you want. The secret is the carriage return
> "\r" at the beginning of the print string. That will bring the cursor
> back to the beginning of the line and then overwrite anything
> currently on that line.
>
Smells unportable between Linux, Windows, and Mac Classic. Then again, I
don't know what approach Ruby takes to newline-handling on non-Unix
platforms.
Ah, the good old days of high-school Turbo Pascal, when gotoxy() Just
Worked (tm). Nary a control character or escape sequence in sight.
David Vallner
Gabriele Marrone
Il giorno 08/nov/06, alle ore 00:15, David Vallner ha scritto:
> Smells unportable between Linux, Windows, and Mac Classic. Then
> again, I
> don't know what approach Ruby takes to newline-handling on non-Unix
> platforms.
A portable way (but maybe overkill for this) is by using the ncurses
library.
I never tried ncurses-ruby, though.
> Ah, the good old days of high-school Turbo Pascal, when gotoxy() Just
> Worked (tm). Nary a control character or escape sequence in sight.
ncurses also has gotoxy :)
>
> David Vallner
--
Gabriele Marrone
Tim Pease
> Tim Pease wrote:
> > That should do you what you want. The secret is the carriage return
> > "\r" at the beginning of the print string. That will bring the cursor
> > back to the beginning of the line and then overwrite anything
> > currently on that line.
> >
>
> Smells unportable between Linux, Windows, and Mac Classic. Then again, I
> don't know what approach Ruby takes to newline-handling on non-Unix
> platforms.
>
"\r" is completely portable. win32 platforms use a "\r\n" for the end
of a line, and *NIX uses just a single "\n" -- hence the dos2unix
utility.
Now, the ANSI control character to clear to the end of a line
(mentioned earlier in this thread) is definitely not portable to the
win32 cmd shell.
TwP
Peña, Botp
# Tim Pease wrote:
# > That should do you what you want. The secret is the carriage return
# > "\r" at the beginning of the print string. That will bring
# the cursor
# > back to the beginning of the line and then overwrite anything
# > currently on that line.
#
# Smells unportable between Linux, Windows, and Mac Classic.
# Then again, I
# don't know what approach Ruby takes to newline-handling on non-Unix
# platforms.
fyi, code posted by TwP runs on linux and windows.
kind regards -botp
Peña, Botp
# I just tried it out, and that is the correct code :)
# clear = "\e[K"
# print "a very long line of text that is longer than the next line"
# sleep 1
# print "\rshort line of text#{clear}"
# sleep 1
# print "\n"
i just do something like
MAX=foo_integer||80
CR="\r"
s=foo_string[0..MAX].ljust(MAX) #or rjust or center
print CR+s
kind regards -botp