getting end of string

[Simon Krahnke]

Hi,

I have a string s and I'm only interested in everything in it after the
first character.

So at the moment I do

| s[1,128].bytes

Just putting 128 as the length cause that's probably bigger than
anything I'll ever enter into my tool. But there's gotta be a better way
of doing that except going to Regexps.

mfg, simon .... confused

[Doc O'Leary]

In article <87txmwc...@xts.gnuu.de>,

Depending on your needs, these spring to mind:

>> here = "this is a string for you"
=> "this is a string for you"
>> here[1,here.length]
=> "his is a string for you"
>> here[1..-1]
=> "his is a string for you"
>> here[0] = ""
=> ""
>> here
=> "his is a string for you"

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[Simon Krahnke]

* Doc O'Leary <drolear...@2q2013.subsume.com> (18:13) schrieb:

>In article <87txmwc...@xts.gnuu.de>,
> Simon Krahnke <over...@gmx.li> wrote:
>
>> I have a string s and I'm only interested in everything in it after the
>> first character.
>>
>> So at the moment I do
>>
>> | s[1,128].bytes
>>
>> Just putting 128 as the length cause that's probably bigger than
>> anything I'll ever enter into my tool. But there's gotta be a better way
>> of doing that except going to Regexps.
>
> Depending on your needs, these spring to mind:
>
>>> here = "this is a string for you"
>=> "this is a string for you"
>>> here[1,here.length]
>=> "his is a string for you"
>>> here[1..-1]

Thank you, I like this one. Didn't come to my mind, that the Range would
do it.

>=> "his is a string for you"
>>> here[0] = ""
>=> ""
>>> here
>=> "his is a string for you"

It's the start of a chain of operations in one line. Likes this:

| when /^h/ then s[1..-1].scan(/../).map { | d | d.hex }

mfg, simon .... binshow.rb replaces binshow.pl