What if I need to check if there is a file that contains "HV" in the
filename? What should I do?
Thank you,
Sang-Ho
<code>
from __future__ import print_function
import os
for filename in os.listdir( "." ):
if "HV" in filename.upper():
print( filename )
</code>
Cheers & hth.,
- Alf
Or learn the glob module. It allows you to ask for a list of files
matching a pattern that can include wildcard characters -- probably
"*HV*" for your case.
Gary Herron
re.search("HV", filename)
would be better and:
"HV" in filename.upper()
would be even better, as Alf posted.
> --
> http://mail.python.org/mailman/listinfo/python-list
>
>
NAME
glob - Filename globbing utility.
FILE
/usr/lib64/python2.6/glob.py
FUNCTIONS
glob(pathname)
Return a list of paths matching a pathname pattern.
The pattern may contain simple shell-style wildcards a la fnmatch.
iglob(pathname)
Return an iterator which yields the paths matching a pathname
pattern.
The pattern may contain simple shell-style wildcards a la fnmatch.
DATA
__all__ = ['glob', 'iglob']
-------------------
solution:
import glob
for afile in glob.iglob( "/home/buddy/*.HV" ):
print afile
sph
On 03/15/2010 08:44 AM, MRAB wrote:
> Lan Qing wrote:
>> Or use the regular module:
>>
>> import re
>> import os
>>
>> for filename in os.listdir('.'):
>> if re.match("*HV*", filename):
>> # do something with the file
>>
> The regular expression should be ".*HV.*", although:
>
> re.search("HV", filename)
>
> would be better and:
>
> "HV" in filename.upper()
>
> would be even better, as Alf posted.
>
>> On Mon, Mar 15, 2010 at 12:24 PM, Alf P. Steinbach <al...@start.no
>> <mailto:al...@start.no>> wrote:
>>
>> -- http://mail.python.org/mailman/listinfo/python-list
>>
>>
>