How would I do a continuous write over a pipe in the following code...

[chad]

Given the following....

#!/usr/bin/python

import subprocess as s

broadcast = s.Popen("echo test | wall", shell=True,stdout=s.PIPE)

out = broadcast.stdout
while 1:
out
broadcast.wait()

broadcast.stdout.close()

The code only executes once. What I want to do is be able to
continuously write over the pipe once it is open. I could put
s.Popen() inside the while loop, but that seems a bit too messy. So is
there some way to just open the pipe once, and once it is open, just
continuously write over it vs just opening and closing the pipe every
time?

[Chris Rebert]

On Sun, Feb 21, 2010 at 1:09 PM, Dennis Lee Bieber
<wlf...@ix.netcom.com> wrote:
> On Sat, 20 Feb 2010 12:46:24 -0800 (PST), chad <cda...@gmail.com>
> declaimed the following in comp.lang.python:

>
>> Given the following....
>>
>> #!/usr/bin/python
>>
>> import subprocess as s
>>
>> broadcast = s.Popen("echo test | wall", shell=True,stdout=s.PIPE)
>>
>> out = broadcast.stdout
>> while 1:
>>     out
>

>        Does nothing... "out" is a name bound to the object identified by
> "broadcast.stdout"...
>
>        It does nothing unless it is called as...
>
>        out(somedata)

I'm pretty sure you meant:

out.write(somedata)

Cheers,
Chris
--
http://blog.rebertia.com

[Aahz]

In article <9d0f6456-97c7-4bde...@t31g2000prh.googlegroups.com>,

You really should do this instead, untested:

broadcast = s.Popen(['wall'], stdin=s.PIPE)
while 1:
broadcast.write('test\n')
time.sleep(1)
--
Aahz (aa...@pythoncraft.com) <*> http://www.pythoncraft.com/

"Many customs in this life persist because they ease friction and promote
productivity as a result of universal agreement, and whether they are
precisely the optimal choices is much less important." --Henry Spencer