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Message from discussion Unpaking Tuple
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Chris Rebert  
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 More options Oct 6 2012, 6:27 am
Newsgroups: comp.lang.python
From: Chris Rebert <c...@rebertia.com>
Date: Sat, 6 Oct 2012 03:27:52 -0700
Local: Sat, Oct 6 2012 6:27 am
Subject: Re: Unpaking Tuple
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On Sat, Oct 6, 2012 at 3:09 AM, sajuptpm <sajup...@gmail.com> wrote:
> Hi,

> I am using python 2.6.

> I need a way to make following code working without any ValueError .
>>>> a, b, c, d = (1,2,3,4)
>>>> a, b, c, d = (1,2,3).

> Note: Number of values in the tuple will change dynamically.

Then you arguably want a list, not a tuple.

But at any rate:
shortfall = 4 - len(your_tuple)
your_tuple += (None,) * shortfall # assuming None is a suitable default
a, b, c, d = your_tuple

If you also need to handle the "too many items" case, use slicing:
a, b, c, d = your_tuple[:4]

Cheers,
Chris


 
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