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Message from discussion syntax for code blocks
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Kiuhnm  
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 More options Apr 27 2012, 7:24 am
Newsgroups: comp.lang.python
From: Kiuhnm <kiuhnm03.4t.yahoo.it>
Date: Fri, 27 Apr 2012 13:24:35 +0200
Local: Fri, Apr 27 2012 7:24 am
Subject: syntax for code blocks
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I'd like to change the syntax of my module 'codeblocks' to make it more
pythonic.

Current Syntax:

     with res << func(arg1) << 'x, y':
         print(x, y)

     with res << func(arg1) << block_name << 'x, y':
         print(x, y)

New Syntax:

     with res == func(arg1) .taking_block (x, y):
         print(x, y)

     with res == func(arg1) .taking_block (x, y) as block_name:
         print(x, y)

The full form is equivalent to

     def anon_func(x, y):
         print(x, y)
     res = func(arg1, block_name = anon_func)

Suggestions?

Kiuhnm


 
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