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groveling over a file for Q:: and A:: stmts

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paul618

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Jul 24, 2012, 3:50:22 AM7/24/12
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#!/usr/bin/env python
# grep_for_QA.py I am only looking to isolate uniq Q:: and A:: stmts from my daily files
#
# note: This algorithm will fail if there are any blank lines within the Q and A area of interest (a paragraph)

# D. Beazley is my fav documentation

import re, glob
import pprint as pp

sampledata = '''
A:: And Straight Street is playin on the Radio Free Tibet. What are the chances, DTMB?
Q:: About 1 in 518400, Professor.
A:: Correct! Err, I thought it was 1:410400, but <i>close enough for jazz!</i>


'''

pattern0 = re.compile("Q::")
pattern1 = re.compile("A::") # objects of interest can start with A:: ;; not alway Q::
END_OF_PARAGRAPH_pat = "\n\s*\n"

path = "/Users/paultaney/dailies2012/0722" # an example of real data set.

toggle = False
L = []
M = []

#file = open(path, "r")
try:
#for line in file.readlines():
for line in sampledata:
try:
# Later, I also need to treat Unicode -- and I am clueless.

# falsestarts::
#line.encode("utf8").decode('xxx', 'ignore')
#line.encode("utf8", 'ignore')
#line.decode('8859')
#line.decode('8859') # 8859, Latin-1 doesn't cover my CJK pastings AT ALL
#line.decode('GB18030') # 171006 -- ack
#encoded_line = line # xxx line.encode("utf8")

mo0 = re.search(pattern0, line)
mo1 = re.search(pattern1, line)
mo2 = re.search(END_OF_PARAGRAPH_pat, line)

if mo0:
if 1: print ("I see pattern 0")
toggle = True
if 1: print(line)
M.append(mo0.group())

if mo1:
if 1: print ("I see pattern 1")
toggle = True
M.append(mo1.group())

if mo2 and toggle:
if 1: print ("I see pattern 2 AND toggle is set")
# got one. save it for uniqifying, and empty the container
toggle = False
L.append(M)
M = []

except Exception as e:
print("--- " + e + " ---")

except UnicodeDecodeError:
#encoded_line = encoded_line.urlsafe_b64encode(re.replace("asdf", encoded_line))
#line = re.sub(".+", "--- asdf ---", line)
pass

L.sort
print (L)

# and what"s wrong with some of this, here!
#myHash = set(L) # uniqify
#pp.pprint(myHash) # july 23, 131001 hike!

Steven D'Aprano

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Jul 24, 2012, 4:21:08 AM7/24/12
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On Tue, 24 Jul 2012 00:50:22 -0700, paul618 wrote:

> #!/usr/bin/env python
> # grep_for_QA.py I am only looking to isolate uniq Q:: and A:: stmts
> from my daily files #
> # note: This algorithm will fail if there are any blank lines within
> the Q and A area of interest (a paragraph)
>
> # D. Beazley is my fav documentation


If you are going to ask a question, please ask a question. Don't just
dump a whole pile of code in our laps and expect us to work out what your
question is.

It may help if you read this page:

http://sscce.org/

Some further comments below:

> import re, glob
> import pprint as pp
>
> sampledata = '''
> A:: And Straight Street is playin on the Radio Free Tibet. What are the
> chances, DTMB? Q:: About 1 in 518400, Professor.
> A:: Correct! Err, I thought it was 1:410400, but <i>close enough for
> jazz!</i>
>
>
> '''
>
> pattern0 = re.compile("Q::")

There is no point in using a regular expression for something as trivial
as that. That is like swinging a 20 kg sledge-hammer to crack a peanut.

Just use a string method:

if my_string.startswith("Q::"): ...


[...]
> # Later, I also need to treat Unicode -- and I am clueless.

If you have a question about Unicode, you should ask it.

If you have not already read this page, you should read it now:

http://www.joelonsoftware.com/printerFriendly/articles/Unicode.html



> except Exception as e:
> print("--- " + e + " ---")

Please don't throw away useful debugging information.

You should learn to read exception tracebacks, not hide them. They
contain a lot of very useful information to help you debug your code.

> except UnicodeDecodeError:
> #encoded_line = encoded_line.urlsafe_b64encode(re.replace("asdf",
> encoded_line)) #line = re.sub(".+", "--- asdf ---", line) pass

This will never be caught because any UnicodeDecodeError will already be
caught by the "except Exception" line above.


> L.sort
> print (L)
>
> # and what"s wrong with some of this, here! #myHash = set(L) #
> uniqify
> #pp.pprint(myHash) # july 23, 131001 hike!

I don't know what's wrong with it. What do you expect it to do, and what
does it actually do instead?



--
Steven

paul618

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Jul 24, 2012, 5:34:08 AM7/24/12
to
Hi Steve:


Thank you for your quick response.

Ah, indeed I failed to ask my question:: Why doesnt this code print the sampledata? Instead it prints the empty list.

The answer is probably quite simple, as I really am an idiot.


Thanks again,
paul


MRAB

unread,
Jul 24, 2012, 8:10:45 AM7/24/12
to pytho...@python.org
On 24/07/2012 08:50, paul618 wrote:
> #!/usr/bin/env python
> # grep_for_QA.py I am only looking to isolate uniq Q:: and A:: stmts from my daily files
> #
> # note: This algorithm will fail if there are any blank lines within the Q and A area of interest (a paragraph)
>
> # D. Beazley is my fav documentation
>
> import re, glob
> import pprint as pp
>
> sampledata = '''
> A:: And Straight Street is playin on the Radio Free Tibet. What are the chances, DTMB?
> Q:: About 1 in 518400, Professor.
> A:: Correct! Err, I thought it was 1:410400, but <i>close enough for jazz!</i>
>
>
> '''
>
> pattern0 = re.compile("Q::")
> pattern1 = re.compile("A::") # objects of interest can start with A:: ;; not alway Q::
> END_OF_PARAGRAPH_pat = "\n\s*\n"
>
> path = "/Users/paultaney/dailies2012/0722" # an example of real data set.
>
> toggle = False
> L = []
> M = []
>
> #file = open(path, "r")
> try:
> #for line in file.readlines():
> for line in sampledata:

sampledata is a string, therefore this is iterating over the string,
which yields characters, not lines. Try using sampledata.splitlines():

for line in sampledata.splitlines():

> try:
> # Later, I also need to treat Unicode -- and I am clueless.
>
> # falsestarts::
> #line.encode("utf8").decode('xxx', 'ignore')
> #line.encode("utf8", 'ignore')
> #line.decode('8859')
> #line.decode('8859') # 8859, Latin-1 doesn't cover my CJK pastings AT ALL
> #line.decode('GB18030') # 171006 -- ack
> #encoded_line = line # xxx line.encode("utf8")
>
> mo0 = re.search(pattern0, line)

This searches for pattern0 anywhere in the line. You really want to
check whether the line starts with pattern0, which is better done with:

line.startswith("Q::")
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