>>> Using a decorator in this manner requires repeating the super class
>>> name.  Perhaps there is a way to get the bases of BarGonk, but I don't
>>> think so, because at the time that the decorator is called, BarGonk is
>>> not yet fully defined.

>> Yes, I tried a few different ways, but within the decorator it seems the
>> function object is quite unaware of what class it is destined for.

> When the decorator is called, the function object is just a function
> object, not a method, so there is no concept of "what class it is
> destined for".

>>>> def dec(func):
> ...     print type(func)
> ...     try:
> ...             print func.im_class
> ...     except:
> ...             print "no im_class"
> ...     return func
> ...
>>>> class Test(object):
> ...     @dec
> ...     def spam(self):
> ...             pass
> ...
> <type 'function'>
> no im_class
>>>> type(Test.spam)
> <type 'instancemethod'>
>>>> Test.spam.im_class
> <class '__main__.Test'>

> I suppose you could try to determine what namespace you're currently when
> the class is created, but that's surely going to be fragile and messy.