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Subject: Re: [newbie] A question about lists and strings
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From: Roman Vashkevich <vashkevic...@gmail.com>
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Date: Fri, 10 Aug 2012 15:06:14 +0400
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To: Mok-Kong Shen <mok-kong.s...@t-online.de>
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10.08.2012, =D7 14:12, Mok-Kong Shen =CE=C1=D0=C9=D3=C1=CC(=C1):

> Am 10.08.2012 11:48, schrieb Roman Vashkevich:
>> [snip]
> >The function .... It takes list by reference and creates a new local
> > str. When it's called with listb and strb arguments, listb is passed
> > by reference and mutated. A string "sss" is concatenated with an
> > empty local str. Nothing more happens. Since local str is not
> > returned by xx(), it can not be expected to be printed out in the
> > statement that follows. What is printed out in the print statement =
is
> > the mutated listb and the global strb.
>=20
> Thanks for the explanation of the output obtained. But this means
> nonetheless that parameters of types lists and strings are dealt with
> in "inherently" (semantically) different ways by Python, right?
>=20
> M. K. Shen
>=20
> --=20
> http://mail.python.org/mailman/listinfo/python-list

DaveA provided a very explicit explanation of how py handles list and =
string objects.
Parameters are handled "inherently" by functions...

RV=