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Message from discussion Extract double in binary file
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Christopher A. Craig  
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 More options Nov 26 2003, 1:01 pm
Newsgroups: comp.lang.python
From: list-pyt...@ccraig.org (Christopher A. Craig)
Date: 26 Nov 2003 12:20:01 -0500
Local: Wed, Nov 26 2003 12:20 pm
Subject: Re: Extract double in binary file
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pascal.par...@free.fr (Pascal) writes:
> I've a binary file with data in it.
> This file come from an old ms dos application (multilog ~ 1980).
> In this application, a field is declared as a 'decimal' (999 999
> 999.99).
> I put 0.00 in the field and save the record to the file.
> When I look in the binary file (with python or an hex editor), the
> field is stored on 8 bytes: 00-00-00-00-00-00-7F-00.
> I try unpack from struct module but the result isn't good.

> Can someone help me?

You're sort of vague here, but I don't think struct is going to help
you regardless.  "decimal" in this case is almost certainly some sort
of BCD, which isn't a standard C struct (and therefore unknown to the
struct module).

You really need to figure out how the data is stored.  Based on your
one example it looks like it's stored as a series of 7 bit values
representing the decimal digits with 0x7f indicating the decimal
point.  If this is correct you could use something like

tstr=''
for c in instr:
  if c == chr(0x7f):
    tstr+='.'
  else:
    tstr += str(ord(c))
fl = float(tstr)

With two major caveats:
  1) that this is going to return a float, not a decimal
  2) There's no way for me to even guess how negative numbers are
     represented

--
Christopher A. Craig <list-pyt...@ccraig.org>
"By rights we shouldn't be here." -- Sam in Peter Jackson's
"The Two Towers" while standing in Osgiliath, where he shouldn't be.


 
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