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What does exc_info do in a logging call?

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Roy Smith

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Feb 23, 2012, 9:21:25 AM2/23/12
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In http://docs.python.org/release/2.6.7/library/logging.html, it says:

logging.debug(msg[, *args[, **kwargs]])
[...]
There are two keyword arguments in kwargs which are inspected: exc_info
which, if it does not evaluate as false, causes exception information to
be added to the logging message. If an exception tuple (in the format
returned by sys.exc_info()) is provided, it is used; otherwise,
sys.exc_info() is called to get the exception information.

I don't get what this is trying to do. I have this code:

try:
f = urllib2.urlopen(url)
except urllib2.HTTPError as ex:
logger.error("Unable to retrieve profile from facebook
(access_token='%r')" % access_token,
exc_info=ex)

which ends up logging:

[...] ERROR _get_profile Unable to retrieve profile from facebook
(access_token='u'[token elided]'')

so what is the exc_info doing? What "exception information" is being
added to the message? Am I just calling this wrong?

Peter Otten

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Feb 23, 2012, 10:05:50 AM2/23/12
to pytho...@python.org
I think whatever the formatter's formatException() makes out of the
(exception_type, exception_value, traceback) tuple lands in the logfile:

>> import logging
>>> logging.basicConfig()
>>> try: 1/0
... except: logging.error("yadda")
...
ERROR:root:yadda
>>> try: 1/0
... except: logging.error("yadda", exc_info=True)
...
ERROR:root:yadda
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ZeroDivisionError: integer division or modulo by zero
>>> class Formatter(logging.Formatter):
... def formatException(self, *args): return "OOPS"
...
>>> logging._handlers.keys()[0].setFormatter(Formatter()) # ;)
>>> try: 1/0
... except: logging.error("yadda", exc_info=True)
...
yadda
OOPS


Roy Smith

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Feb 23, 2012, 10:47:21 AM2/23/12
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Duh, I figured out what's going on. I'm using a custom Formatter class, which overrides format(). It's the job of format() to handle this, and ours doesn't!
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