pySerial
__zip__
I am using pySerial for communication with modem.
Does anyone knows which values are for what in these variables?
xonxoff=0
rtscts=0
dsrdtr=0
if xonxoff=0 is it hardware control on or of (logic says it would be off
, but who knows).
Second question is: do I need to send \n or soemthing when I use write().
I would like to do:
ser.write("AT")
print ser.readline()
and get "OK".
Am I doing soemthing wrong?
tnx in advance.
John Machin
> Hi,
>
> I am using pySerial for communication with modem.
>
> Does anyone knows which values are for what in these variables?
>
> xonxoff=0
> rtscts=0
> dsrdtr=0
>
> if xonxoff=0 is it hardware control on or of (logic says it would be off
> , but who knows).
Disclaimer: It's a long time since I bit-bashed a UART ...
Where those relate to bits in the control registers, I'd expect 1 maps
to 1 and 0 maps to 0. Where they relate to functionality provided by
the software, I'd expect 1 to mean "do it" and 0 to mean "don't do
it". Do you have any reason for assuming otherwise?
>
> Second question is: do I need to send \n or soemthing when I use write().
That depends on what the modem is expecting.
>
> I would like to do:
>
> ser.write("AT")
> print ser.readline()
>
> and get "OK".
And what did you get"?
>
> Am I doing soemthing wrong?
Probably what you are doing wrong is not reading the docs.
http://pyserial.sourceforge.net/
"""Be carefully when using "readline". Do specify a timeout when
opening the serial port otherwise it could block forever if no newline
character is received. Also note that "readlines" only works with a
timeout. "readlines" depends on having a timeout and interprets that
as EOF (end of file). It raises an exception if the port is not opened
correctly.
"""
When you have a problem, show all the code (including the opening and
configuring of the port) and tell us what did happen with that code.
__zip__
The problem was that returning bytes were on few lines and I
didn't look after first \n :(
tnx.
[david]
Just a note:
Most modems expect CR (\r), rather than \n.