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Message from discussion FAQ 4.40 What is the difference between $array[1] and @array[1]?
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 More options May 13, 9:03 am
Newsgroups: comp.lang.perl.misc
From: PerlFAQ Server <br...@stonehenge.com>
Date: Tue, 13 May 2008 06:03:02 -0700
Local: Tues, May 13 2008 9:03 am
Subject: FAQ 4.40 What is the difference between $array[1] and @array[1]?
This is an excerpt from the latest version perlfaq4.pod, which
comes with the standard Perl distribution. These postings aim to
reduce the number of repeated questions as well as allow the community
to review and update the answers. The latest version of the complete
perlfaq is at http://faq.perl.org .

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4.40: What is the difference between $array[1] and @array[1]?

    The former is a scalar value; the latter an array slice, making it a
    list with one (scalar) value. You should use $ when you want a scalar
    value (most of the time) and @ when you want a list with one scalar
    value in it (very, very rarely; nearly never, in fact).

    Sometimes it doesn't make a difference, but sometimes it does. For
    example, compare:

            $good[0] = `some program that outputs several lines`;

    with

            @bad[0]  = `same program that outputs several lines`;

    The "use warnings" pragma and the -w flag will warn you about these
    matters.

--------------------------------------------------------------------

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so please include as much information as possible and relevant in any
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Working code is greatly appreciated.

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