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Message from discussion LISP - 2 exponent 0 = 1
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Thomas Stegen  
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 More options Sep 17 2002, 3:58 am
Newsgroups: comp.lang.lisp
From: Thomas Stegen <tste...@cis.strath.ac.uk>
Date: Tue, 17 Sep 2002 08:58:20 +0100
Local: Tues, Sep 17 2002 3:58 am
Subject: Re: LISP - 2 exponent 0 = 1
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ilias wrote:
> Thien-Thi Nguyen wrote:

>> ilias <at_n...@pontos.net> writes:

>>> explain.

>> done.  understand.

>> thi

> your explanation.

> was not for me.

> it was for you.

You cannot multiply apples with apples. Here is
a more mathematical explanation. ^ is the expt
operator.

a^b / a^c = a^(b - c)   Check this one for yourself
                         if you don't believe me

a^0 = a^(b - b)         b = c since they must subtract
                         to zero

     = a^b / a^b         A number divided by itself is always 1

     = 1

This is not a proof untill you prove the first equation.
That has been done time and time again though and is very
intuitive so that should be no problem.

HTH.

--
Thomas Stegen


 
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