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SPLIT numbers into sub-numbers
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k_ghr...@yahoo.com  
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 More options Jun 22 2012, 3:52 pm
Newsgroups: comp.lang.idl-pvwave
From: k_ghr...@yahoo.com
Date: Fri, 22 Jun 2012 12:52:48 -0700 (PDT)
Local: Fri, Jun 22 2012 3:52 pm
Subject: SPLIT numbers into sub-numbers
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Dear all
I would like to split the following number 20100115 into year, month
and day
any suggestions
Thanks

 
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Michael Galloy  
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 More options Jun 22 2012, 5:02 pm
Newsgroups: comp.lang.idl-pvwave
From: Michael Galloy <mgal...@gmail.com>
Date: Fri, 22 Jun 2012 15:02:02 -0600
Local: Fri, Jun 22 2012 5:02 pm
Subject: Re: SPLIT numbers into sub-numbers
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On 6/22/12 1:52 PM, k_ghr...@yahoo.com wrote:

> Dear all
> I would like to split the following number 20100115 into year, month
> and day
> any suggestions
> Thanks

Something like this:

IDL> ts = '20100115'
IDL> year = long(strmid(ts, 0, 4))
IDL> month = long(strmid(ts, 4, 2))
IDL> day = long(strmid(ts, 6, 2))
IDL> help, year, month, day
YEAR            LONG      =         2010
MONTH           LONG      =            1
DAY             LONG      =           15

Mike
--
Michael Galloy
www.michaelgalloy.com
Modern IDL: A Guide to IDL Programming (http://modernidl.idldev.com)
Research Mathematician
Tech-X Corporation


 
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Kenneth P. Bowman  
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 More options Jun 22 2012, 9:45 pm
Newsgroups: comp.lang.idl-pvwave
From: "Kenneth P. Bowman" <k-bow...@null.edu>
Date: Fri, 22 Jun 2012 20:45:01 -0500
Local: Fri, Jun 22 2012 9:45 pm
Subject: Re: SPLIT numbers into sub-numbers
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In article <js2mga$jh...@dont-email.me>, Michael Galloy <mgal...@gmail.com>
wrote:

Or

year  = 0
month = 0
day   = 0
READS, ts, year, month, day, FORMAT = "(I4,2I2)"

Cheers, Ken


 
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k_ghr...@yahoo.com  
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 More options Jun 23 2012, 2:59 pm
Newsgroups: comp.lang.idl-pvwave
From: k_ghr...@yahoo.com
Date: Sat, 23 Jun 2012 11:59:30 -0700 (PDT)
Local: Sat, Jun 23 2012 2:59 pm
Subject: Re: SPLIT numbers into sub-numbers
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On Jun 23, 3:45 am, "Kenneth P. Bowman" <k-bow...@null.edu> wrote:

Thanks for your help
first you convert a long number to a string by put it between '  '

but if i have a long array like this
20100101    20100101    20100101    20100101    20100102
20100102    20100102    20100102    20100103    20100103
20100103    20100103    20100104

and I cann't put each sub group between ' '
how I can split this directly?
Best wishes
Khaled


 
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k_ghr...@yahoo.com  
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 More options Jun 23 2012, 2:59 pm
Newsgroups: comp.lang.idl-pvwave
From: k_ghr...@yahoo.com
Date: Sat, 23 Jun 2012 11:59:55 -0700 (PDT)
Local: Sat, Jun 23 2012 2:59 pm
Subject: Re: SPLIT numbers into sub-numbers
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On Jun 22, 11:02 pm, Michael Galloy <mgal...@gmail.com> wrote:

Thanks for your help
first you convert a long number to a string by put it between '  '

but if i have a long array like this
20100101    20100101    20100101    20100101    20100102
20100102    20100102    20100102    20100103    20100103
20100103    20100103    20100104

and I cann't put each sub group between ' '
how I can split this directly?
Best wishes
Khaled


 
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Carsten Lechte  
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 More options Jun 23 2012, 5:13 pm
Newsgroups: comp.lang.idl-pvwave
From: Carsten Lechte <c...@toppoint.de>
Date: Sat, 23 Jun 2012 23:13:56 +0200
Local: Sat, Jun 23 2012 5:13 pm
Subject: Re: SPLIT numbers into sub-numbers
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On 23/06/12 03:45, Kenneth P. Bowman wrote:

> year  = 0
> month = 0
> day   = 0
> READS, ts, year, month, day, FORMAT = "(I4,2I2)"

Nice, I had not thought of that.

My first idea was:

num = 20100115L ; very important: force LONG integer type!
y = num/10000
m = (num-y*10000)/100
d = num - y*10000 - m*100
print, num, y, m, d

==>    20100115        2010           1          15

chl


 
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k_ghr...@yahoo.com  
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 More options Jun 23 2012, 6:08 pm
Newsgroups: comp.lang.idl-pvwave
From: k_ghr...@yahoo.com
Date: Sat, 23 Jun 2012 15:08:02 -0700 (PDT)
Local: Sat, Jun 23 2012 6:08 pm
Subject: Re: SPLIT numbers into sub-numbers
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On Jun 23, 11:13 pm, Carsten Lechte <c...@toppoint.de> wrote:

for the following array
20100101    20100101    20100101    20100101    20100102
20100102    20100102    20100102    20100103    20100103
20100103    20100103    20100104

 I wrote

y=lonarr( n_elements(num))
m =lonarr( n_elements(num))
d =lonarr( n_elements(num))
for i = 0, n_elements(num)-1 do begin
num(i)=num(i)+0L

y(i) = num(i)/10000
m(i) = (num(i)-y(i)*10000)/100
d(i) = num(i) - y(i)*10000 - m(i)*100
print, num(i), y(i), m(i), d(i)
endfor

and now ran correctly with the following output
    20100101        2010           1           1
    20100101        2010           1           1
    20100101        2010           1           1
    20100101        2010           1           1
    20100102        2010           1           2
    20100102        2010           1           2
    20100102        2010           1           2
    20100102        2010           1           2
    20100103        2010           1           3
    20100103        2010           1           3
    20100103        2010           1           3
    20100103        2010           1           3
    20100104        2010           1           4
thank you for your helping


 
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alx  
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 More options Jun 24 2012, 4:36 am
Newsgroups: comp.lang.idl-pvwave
From: alx <lecacheux.al...@wanadoo.fr>
Date: Sun, 24 Jun 2012 01:36:14 -0700 (PDT)
Local: Sun, Jun 24 2012 4:36 am
Subject: Re: SPLIT numbers into sub-numbers
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On 22 juin, 21:52, k_ghr...@yahoo.com wrote:

> Dear all
> I would like to split the following number 20100115 into year, month
> and day
> any suggestions
> Thanks

The "IDL way" for extracting dates from such a coded integer array
might be:

IDL> dates = transpose([[x/10000],[(x mod 10000)/100],[x mod 100]])
in which dates will be an array of dimensions 3 x N_elements(x).

for instance:
IDL> x = [20100401, 20110501, 20120601]
IDL> print, transpose([[x/10000],[(x mod 10000)/100],[x mod 100]])
        2010           4           1
        2011           5           1
        2012           6           1

A maybe more "readable", but slower way would be:

IDL> dates = intarr(3,N_elements(x))    ;you must define your output
first
IDL> reads, string(x, FORMAT='(i8)'), dates, FORMAT='(i4,i2,i2)'

or, if you like Julian days:

IDL> jd = dblarr(3,N_elements(x))    ;you must define your output
first
IDL> reads, string(x, FORMAT='(i8)'), jd,
FORMAT='(C(CYI4,CMOI2,CDI2))'
IDL> print,jd
       2455288.0       2455683.0       2456080.0

alx.


 
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