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ML: psychological basis of language ranking?
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From: torb...@diku.dk (Torben Ęgidius Mogensen)
Newsgroups: comp.lang.functional
Subject: Re: ML: psychological basis of language ranking?
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Date: Fri, 19 Oct 2012 09:58:34 +0200
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Avoid9...@gmail.com writes:
> What does Harper mean?
> I'll try to interpret this first/easier one, my self:
> ]Object-oriented programming is eliminated entirely from the
> ]introductory curriculum, because it is both anti-modular and
> ]anti-parallel by its very nature, and hence unsuitable for a modern
> ]CS curriculum.
> Does he mean, that since the essence of OO is that objects
> are defined [hence dependant on] by their ancestor, knowledge
> about an object can't be decoupled from knowledge about its
> ancestors?
I don't think so. Objects are anti-paralllel because the fundamental
operation on modules is reading and updating storage local to the
object. I'm not sure what in particular makes him call them
anti-modular, but it might be for much the same reason: If there is
local mutable state in objects, you can't compose them freely, as a use
of the object in one place can affect another use of the same object in
another place in a way that you can't predict from its interface.
> Yes, for me, the freedon to NOT be-concerned-about
> side issues is a MASSIVE advantage for any programming
> system. And the ability to 'pipe/data-transform' sequentially
> like forth, and at tested/confirmed stageN not to need to
> be-concerned-about stageN-2.
>
> Does ML support such a [concatenative] style?
If I understand you correctly, it does. Function composition is natural
and easy in ML.
> ====> Then in
> http://existentialtype.wordpress.com/tag/type-theory/
> he writes: [in my simplified non-LaTex notation]
>
>>In languages we have the fundamental concept of a typing judgement, written
>> x1:A1,...xn:An => M:A
>> stating that M is an expression of type A involving variables xi of type Ai.
>
> That's OK.
>>
>>A typing judgement must satisfy the following basic structural properties:
>> x:A => x:A
>>
>> y:B => N:C x:A => M:B
>>-----------------------
>> x:A => [M/y]N:C
>>
>> We may think of the variables as names for "libraries", in which
>> case the first states that we may use any library we wish, and the
>> second states closure under "linking" (as in the Unix tool ld or its
>> relatives), with [M/x]N being the result of linking x in N to the
>> library M .
>
> Let's try to unpick that, in steps:
> y:B => N:C
> means N is an expression of type C involving variable y of type B
> x:A => M:B
> means M is an expression of type B involving variable x of type A
>
> By `"linking" (as in the Unix tool ld)`, does he mean 'replace the
> expression, with the code-which-implements it'?
>
> What is his main point?
The main point is that types act as contracts: If you replace a variable
of type B with an expression of type B, this will not yield typpe errors
and the type of the surrounding expression should not change by this
exchange. Basically, An expression of type B has the same type in every
context (assuming free variables, in this case x, do not change their
type in the different contexts).
Torben