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Message from discussion Is this legal?
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Salvatore  
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 More options May 29 2008, 10:03 am
Newsgroups: comp.lang.fortran
From: Salvatore <sfilipp...@uniroma2.it>
Date: Thu, 29 May 2008 07:03:55 -0700 (PDT)
Local: Thurs, May 29 2008 10:03 am
Subject: Is this legal?
Hi,
subject says all: is the attached code legal? two compilers accept it,
one does not.

Thanks
Salvatore
 ---------------------------------------- usemod2.f90
-------------------
module s_type_mod
  type s_foo_type
    real(kind(1.e0)), allocatable :: v(:)
  end type s_foo_type
end module s_type_mod
module s_foo_mod
  use s_type_mod
  interface foobar
    subroutine s_foobar(x)
      use s_type_mod
      type(s_foo_type), intent (inout) :: x
    end subroutine s_foobar
  end interface
end module s_foo_mod

module d_type_mod
  type d_foo_type
    real(kind(1.d0)), allocatable :: v(:)
  end type d_foo_type
end module d_type_mod

module d_foo_mod
  use d_type_mod

  interface foobar
    subroutine d_foobar(x)
      use d_type_mod
      type(d_foo_type), intent (inout) :: x
    end subroutine d_foobar
  end interface
end module d_foo_mod

module foo_mod
  use s_foo_mod
  use d_foo_mod
end module foo_mod

subroutine s_foobar(x)
  use foo_mod, protect => s_foobar
  type(s_foo_type), intent (inout) :: x

  if (.not.allocated(x%v)) allocate(x%v(10))
end subroutine s_foobar

subroutine d_foobar(x)
  use foo_mod, protect => d_foobar
  type(d_foo_type), intent (inout) :: x

  if (.not.allocated(x%v)) allocate(x%v(10))
end subroutine d_foobar

program test
  use foo_mod
  type(d_foo_type) :: z

  call foobar(z)

end program test


 
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