overloading operator== and casting

[Popping mad]

I have two object type that I wanted to compare to each other using the
operator== but to my surprise, which I compiled it, I got a complaint
about the different types being used without cast


euler.cpp|113 col 28| error: comparison between distinct pointer types
‘tree::Predicate<int, int>*’ and ‘tree::Node<int>*’ lacks a cast


my overload operator knows this already

class Predicate{
public:
Predicate(Node<node_type>& in_a, Node<node_type>& in_b,
Edge<bridge_type>& in_c)
: a{in_a}, b{in_b}, c{in_c}{
a.data++;
b.data++;
};
...

bool operator==(const Node<node_type>& first)

Can anyone suggest the cleanest means of working around this annoying
error.

[Alf P. Steinbach]

You can't overload `==` for raw pointer types, and you're not doing
that. Your overload is for references/values.


Cheers!,

- Alf

[Juha Nieminen]

Popping mad <rai...@colition.gov> wrote:
> euler.cpp|113 col 28| error: comparison between distinct pointer types

> ???tree::Predicate<int, int>*??? and ???tree::Node<int>*??? lacks a cast

You are comparing pointers, not values.

Are you sure you didn't intend to write "*ptr1 == *ptr2"
instead of "ptr1 == ptr2"?

[ruben safir]

On 02/21/2017 07:08 AM, Juha Nieminen wrote:
> You are comparing pointers, not values.
>
> Are you sure you didn't intend to write "*ptr1 == *ptr2"
> instead of "ptr1 == ptr2"?

that is a good suggestion, but I fixed this a week ago and forgot how I
fixed it already

[Öö Tiib]

And also you already deleted the file and so you can't look into it to
figure out how you fixed it.