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ifstream::open
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Doug Mika
Apr 20, 2015, 12:35:57 PM4/20/15
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The definition of std::ifstream::open is as follows
(according to www.cplusplus.com & www.cppreference.com):
void open (const char* filename, ios_base::openmode mode = ios_base::in);
void open (const string& filename, ios_base::openmode mode = ios_base::in);
this means that both the open member functions take two parameters. HOWEVER, I can open a stream as follows:
ifstream inFile;
inFile.open("input.dat");
Why isn't the open member function that takes one parameter part of the www.cplusplus.com std::ifstream::open definition?
(according to www.cplusplus.com & www.cppreference.com):
void open (const char* filename, ios_base::openmode mode = ios_base::in);
void open (const string& filename, ios_base::openmode mode = ios_base::in);
this means that both the open member functions take two parameters. HOWEVER, I can open a stream as follows:
ifstream inFile;
inFile.open("input.dat");
Why isn't the open member function that takes one parameter part of the www.cplusplus.com std::ifstream::open definition?
Victor Bazarov
Apr 20, 2015, 12:52:33 PM4/20/15
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V
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