Template friend of templated class

[Juha Nieminen]

This compiles ok:

//------------------------------------------------------------
struct Test
{
template<typename T>
friend Test friendFunc(T);

private:
int value;
};

template<typename T>
Test friendFunc(T value)
{
Test test;
test.value = value;
return test;
}

int main() { friendFunc(10); }
//------------------------------------------------------------

However, this does not:

//------------------------------------------------------------
template<typename R>
struct Test
{
template<typename T>
friend Test<R> friendFunc(T);

private:
int value;
};

template<typename T>
Test<T> friendFunc(T value)
{
Test<T> test;
test.value = value;
return test;
}

int main() { friendFunc(10); }
//------------------------------------------------------------

It complains that the member variable is private.

How to make the second example compile as well?

[Chris Vine]

If you change the friendship declaration of friendFunc in Test to:

template<typename T> friend Test<T> friendFunc(T);

so that it matches the definition, it will compile. The templatizing
of Test on R is pointless and presumably you really want the 'value'
member to be of type R?

Chris