Fwd: C++

[Vir Campestris]

Given
template <typename T> void bazz(T) {};

Why does
        auto foo = std::bind(bazz, 42);
not deduce the template param? You have to say
        auto foo = std::bind(bazz<int>, 42);

It's probably correct behaviour, but it's a right PITA.

Andy

[Alf P. Steinbach]

You can do this, though:

auto foo = [](){ bazz( 42 ); };

Cheers & hth.,

- Alf

[Vir Campestris]

This time it doesn't. That's cut down from some code that takes an
argument pack as well, and they don't seem to sit well with lambdas.

BTW Someone at work pointed out to me you can say
auto foo = []{ bazz( 42 ); };
leaving out one set of brackets.

Andy