>> in my subject-methode detach(const observer& o) i used following line to
>> remove the observer:

>> observers.remove_if([](MyObserver mo){ return &o == &mo; });

>> gcc 4.7 (mingw) give me the error: 'mo' is not captured. what does this
>> mean and how can i achieve the desired behavior?

> Please post real code the next time.

> First of all, the function parameter is passed by value which is
> probably NOT what you want. Secondly, I believe that you named your
> function parameter "o" instead of "mo". Then, the error messages
> actually makes sense because the observer you want to delete is not
> known to the lambda because you havn't captured this information.

> I am GUESSING (because you did not post the relevant information) that
> you should have written

>    observers.remove_if([&mo](MyObserver const& o){return &o == &mo;});

> I'm guessing observers is some kind of list and somehow you got hold of
> reference (mo) to the list element you want to remove. How about
> changing this to an iterator instead? Then, you could just remove it
> like this:

>    list<MyObserver>::iterator mo_iter = ...;
>    :::
>    observers.erase(mo_iter);

> and get rid of the linear search (remove_if).

> Cheers!
> SG