Hi, How do you initialize a pointer to an array? If I have: int x[2] = {5, 10}; and int (*p)[2]; How can I get 'p' to point to 'x'? Here are my attempts, they both seem ugly? Thanks, Joe
void f1() { int x[2] = {5, 10}; int (*p)[2] = reinterpret_cast<int (*)[2]>(x);
}
void f2() { int x[2] = {5, 10}; int a[1][2] = {x[0], x[1]}; int (*p)[2] = a;
> "Joseph Hesse" <joe_he...@actcx.com> wrote in message > news:LL8f8.34$XA5.103910@news.uswest.net... > > Hi, > > How do you initialize a pointer to an array? > > If I have: > > int x[2] = {5, 10}; > > and > > int (*p)[2]; > > How can I get 'p' to point to 'x'?
> > How do you initialize a pointer to an array? > > If I have:
> > int x[2] = {5, 10};
> > and
> int *p = x;
He was asking about a pointer to an array of int, which is different from a pointer to int. This is not used frequently but it can provide better type checking when the size of an array is known at compile- time.
> > How can I get 'p' to point to 'x'?
> There is an implicit conversion from int[] to int* > but it is probably better to make the conversion explicit:
> int *p = (int*)x;
Superfluous casts are never better when there is an implicit conversion.
> There is an implicit conversion from int[] to int* > but it is probably better to make the conversion explicit:
> int *p = (int*)x;
GAK....I'm all for making the conversion explicit, but doing so with a C-style cast opens up too many problems if x happens to inadvertantly be an incompatible type.
