The difference between new node() and new node?

[remlostime]

now, I define the struct following:
struct node
{
bool match;
node* child[27];
};

What's the difference between
1) node *Trie=new node(); and 2) node *Trie = new node;

[Linlin Yan]

no difference.

[James Kanze]

new Node() zero initializes the data, i.e. match will be false,
and all of the pointers will be NULL. new Node doesn't; the
contents are undefined, and reading them (before having set them
otherwise) is undefined behavior.

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James Kanze (GABI Software) email:james...@gmail.com
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[Juha Nieminen]

James Kanze wrote:
> new Node() zero initializes the data, i.e. match will be false,
> and all of the pointers will be NULL. new Node doesn't

Btw, is there anything equivalent for allocating arrays?

[Thomas J. Gritzan]

Juha Nieminen schrieb:

Sure.

// allocates uninitialized ints
int* arry1 = new int[100];

// allocates ints initialized to 0 on recent (=conformant) compilers
int* arry2 = new int[100]();

// allocates ints initialized to 0 on all compilers
std::vector<int> arry3(100);

--
Thomas