Acessing the "time" Part of time_t Value

[Mike Copeland]

How do I mask out all but the _time_ components of a time_t value?
Specifically, I have the following:
time_t wTime = 1226764757;
I happen to know that this is November 16, 2008 @ 8:59:17, but I have
many other such items from which I want to use only the _time_ portion
(e.g. 8:59:17). How do I eliminate the "date" portions of either the
time_t value or the number I assign to it? TIA

[miso.liptak]

Is number of seconds since midnight what you want? time(0) % 86400?
m.

[Pete Becker]

Use gmtime() or localtime() to convert it to a tm.

--
Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
(www.petebecker.com/tr1book)

[Pete Becker]

The requirement (from the C standard) is that time_t is an "arithmetic
type capable of representing times ...". That's all. It doesn't have to
represent seconds, nor does it have to be based on midnight.

[James Kanze]

That depends on how precise and how portable you have to be.
Not all days have exactly 86400 seconds, and time_t can be any
numeric type, with any representation---if it uses the
representation that was current in MS-DOS, your results are
meaningless, and if it is a double, your solution won't even
compile. (But for a lot of uses, it's adequate. It's what I
currently do---but in my case, even if I'm a minute or so off,
it's no big deal, and I only have to support
Unix-likes---Solaris and Linux.)

--
James Kanze (GABI Software) email:james...@gmail.com
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