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On 24 Apr 2003 19:15:27 -0400, ka...@gabi-soft.de (James Kanze) wrote:
> Any reordering which respects the above constraints is a legal executionYou need to read a bit more carefully. It is only accessing the old value
> path for the abstract machine. If any legal execution path results in
> undefined behavior, the behavior is undefined. Accessing a variable
> that is modified without an intervening sequence point (e.g. a function
> call) other than to determine the new value (which of course, introduces
> implicit ordering due to causal necessity) is undefined behavior.
the gives undefined behavior. Otherwise, j + ++ i would be undefined.
> In this case, one possible ordering is:Put that last read at the top which is also allowed and you have undefined
> read c for incr
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