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world coordinates to GAUSS KRUEGER
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Unbekannt  
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 More options Mar 30 1992, 11:10 am
Newsgroups: comp.infosystems.gis
From: t961...@sun1.LRZ-Muenchen.DE (Unbekannt)
Date: Mon, 30 Mar 1992 16:10:22 GMT
Local: Mon, Mar 30 1992 11:10 am
Subject: world coordinates to GAUSS KRUEGER
Hello everbody,

I have a lot of location points, collected with  GPS in world coordintes.
My mapes here in Germany are in GAUSS KRUEGER coordinates. This causes me
a lot of trouble.

Therefore I am asking you if anybody has a program or knows where to get one
for converting world coordinates into GAUSS KRUEGER format!

Thanx a lot in advance!

Karl

-------------------------------------------------------------------------
Karl  Wild                                  t961...@sun1.lrz-muenchen.de
phone +49-8161-713884              or  k...@tec.agrar.tu-muenchen.dbp.de
fax   +49-8161-714048
-------------------------------------------------------------------------


 
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Ferenc Csillag  
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 More options Mar 30 1992, 2:43 pm
Newsgroups: comp.infosystems.gis
From: Ferenc Csillag <FCSIL...@SUNRISE.BITNET>
Date: Mon, 30 Mar 1992 14:43:00 EST
Subject: Re: world coordinates to GAUSS KRUEGER
On Karl Wild's question:
During the last 47 years the Gauss-Kruger projection has been quite popular
East of the Elba River. In fact ALL military maps...
So try with them first.
I'd guess that all geodesy/cartography books published in that period
would also give you a formula.

*Ferko Csillag
 Geography / Syracuse


 
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Ari T Jolma  
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 More options Apr 3 1992, 3:52 am
Newsgroups: comp.infosystems.gis
From: ajo...@hila.hut.fi (Ari T Jolma)
Date: 3 Apr 92 08:52:19 GMT
Local: Fri, Apr 3 1992 3:52 am
Subject: Re: world coordinates to GAUSS KRUEGER

Here is an algorithm to convert latitude & longitude (world
coordinates?) i.e. (lambda,phi) into Gauss-Krueger -coordinates
centered around some meridian (G-K centered to 27.0 are called
common coordinates or "artillery coordinates"  in Finland, that
is set as Const into the code).

The code is Turbo Pascal and is an member function to class
LatLongCts, which is simply a record of x,y:Double. CommonCts
has same data as LatLongCts (is also a descendentant of the
DoublePoint). The result is in kilometers (XY.y is easting
from Merid and XY.x is northing from equator). The rest should
be clear from the code.

Ari Jolma (ajo...@hila.hut.fi)

---------------------------------------
The code starts from here:
---------------------------------------

Procedure LatLongCts.ConvertToCommonCts(Var XY:CommonCts);
(* Reference: Hirvonen 1972, Matemaattinen geodesia, TKY 305, Otaniemi p.31,67
   original fortran algorithm by Y.Rauste 1985 *)
Type Array1_4OfDouble=Array [1..4] of Double;
Const Merid=27.0;
      b:Array1_4OfDouble=(6367.65450006,-16.10703468,0.01697621,-0.00002227);
      c=26399.93660810;
      ep2=0.6768170197224E-2;
      epsil=1.0E-12;
Var phi,lambda,vd,vd1,temp,phid,xp:Double;
    EndLoop:Boolean;
    i:Integer;
Begin
  lambda:=Degr2Rad(y);
  lambda:=lambda-Degr2Rad(Merid);
  phi:=Degr2Rad(x);
  vd1:=Sqrt(1+ep2*Sqr(Cos(phi)));
  i:=1;EndLoop:=False;
  While (i<1000) and not EndLoop do
  begin
    phid:=ArcTan(Tan(phi)/Cos(vd1*lambda));
    vd:=Sqrt(1+ep2*Sqr(Cos(phid)));
    EndLoop:=Abs(vd-vd1) <= epsil;
    If not EndLoop then
    begin
      vd1:=vd;
      Inc(i);
    end;
  end;
  temp:=Tan(lambda)/vd*Cos(phid);
  XY.y:=c*Log(temp+Sqrt(Sqr(temp)+1))+500;
  XY.x:=b[1]*phid+b[2]*Sin(2*phid)+b[3]*Sin(4*phid)+b[4]*Sin(6*phid);
End;
Ari Jolma                                *    
tel. 451 3831                            *      
ajo...@hila.hut.fi                       *
Building W, HUT, 02150 Espoo, Finland    *


 
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