Account Options

  1. Sign in
The old Google Groups will be going away soon, but your browser is incompatible with the new version.
Google Groups Home
« Groups Home
comp.databases.oracle.misc
+ new post
About this group
Subscribe to this group
This is a Usenet group - learn more
Message from discussion character count in a string
The group you are posting to is a Usenet group. Messages posted to this group will make your email address visible to anyone on the Internet.
Your reply message has not been sent.
Your post was successful
 
From:
To:
Cc:
Followup To:
Add Cc | Add Followup-to | Edit Subject
Subject:
Validation:
For verification purposes please type the characters you see in the picture below or the numbers you hear by clicking the accessibility icon. Listen and type the numbers you hear
 
Charles Hooper  
View profile  
 More options Jan 23 2007, 1:42 pm
Newsgroups: comp.databases.oracle.misc
From: "Charles Hooper" <hooperc2...@yahoo.com>
Date: 23 Jan 2007 10:42:22 -0800
Local: Tues, Jan 23 2007 1:42 pm
Subject: Re: character count in a string
Print | View thread | Show original | Report this message | Find messages by this author

Charles Hooper wrote:
> DA Morgan wrote:
> > Charles Hooper wrote:
> > > Eitan M wrote:
> > >> Hello,
> > >> how can I get a specific character count in a string
> > >> (
> > >> i.e : string is 56222, and I am looking for '2' occurance
> > >> when i do :
> > >> select charcount('56222') should return : 3
> > >> )

> > >> Thanks :)

> > > INSTR is all that you need.  See:
> > > http://download-east.oracle.com/docs/cd/B19306_01/server.102/b14200/f...

> > > Charles Hooper
> > > PC Support Specialist
> > > K&M Machine-Fabricating, Inc.

> > Given the quality of your responses I am going to have to ask ... how.
> > I think Anurag's response is one solution and this would be mine.

> > SELECT LENGTH(TRANSLATE('56222', '2013456789', '2')) FROM dual;

> > Though I can see numerous creative possibilities using regular
> > expressions, etc.
> > --
> > Daniel A. Morgan
> > University of Washington
> > damor...@x.washington.edu
> > (replace x with u to respond)
> > Puget Sound Oracle Users Group
> > www.psoug.org

> Sorry, I misread the question and do not have an answer.  I thought
> that he was looking for the position of the third "2" in a string.

> Ignore this:
> SELECT
>   SUM(SIGN(INSTR('562225622256222','2',1,ROWNUM)))
> FROM
>   DUAL
> CONNECT BY
>   LEVEL<20;

> SUM(SIGN(INSTR('562225622256222','2',1,ROWNUM)))
> -------------
> 9

> Charles Hooper
> PC Support Specialist
> K&M Machine-Fabricating, Inc.

gazzag suggested SUBSTR, looks like that will work also:
SELECT
  SUM(DECODE(SUBSTR('562225622256222',ROWNUM,1),'2',1,0))
FROM
  DUAL
CONNECT BY
  LEVEL<255;

SUM(DECODE(SUBSTR('562225622256222',ROWNUM,1),'2',1,0))
------------------
9

Charles Hooper
PC Support Specialist
K&M Machine-Fabricating, Inc.


 
You must Sign in before you can post messages.
To post a message you must first join this group.
Please update your nickname on the subscription settings page before posting.
You do not have the permission required to post.
Create a group - Google Groups - Google Home - Terms of Service - Privacy Policy
©2013 Google