anonymous functions with names

[Erlis Vidal]

Hi guys, 

I've been reading but I'm still confused about the difference between an anonymous function with name vs a defn function

(fn my-func1[x] x)

(defn my-func2[x] x)

Thanks, 

Erlis 

[Baishampayan Ghose]

In case of a named anonymous function the name is only bound in the lexical scope of the anonymous function being defined.

This is useful when defining recursive anonymous functions.

Sent from phone. Please excuse brevity.

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[Tamreen Khan]

The name given an anonymous function can only be used within the scope of that function.

This will work:

(fn my-func1 [x] (my-func x)) ; Leads to infinite recursion, of course

This won't work because my-func1 is called outside of the function's lexical scope:

(fn my-func1 [x] x)

(my-func1 100)

However, functions defined with defn use a global var, so they're not limited to any particular lexical scope.

Erlis 

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[Erlis Vidal]

Thank you guys!!

On Fri, Aug 31, 2012 at 11:59 AM, Jim - FooBar(); <jimpi...@gmail.com> wrote:

defn will create a global var while fn won't...it is only visible in the scope it was originally defined...remember you can always do:

(def f (fn [x] ...)) which is he same as defn

Jim

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[dmirylenka]

Just 2 cents:

A name you give to the anonymous function also appears in the stack traces instead of the things like fn_123_4532,

which is very convenient for debugging.

[Stathis Sideris]

Thanks, this is a *very* useful bit of information.

[Mayank Jain]

@dmirylenka
Thanks. That is useful to know.

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